3 years ago

Znajdź wszystkie rozwiązania x^4-16=0

Mathematics

1 answer:

Brut [27]3 years ago

3 0

Huh? Can you say that in English

You might be interested in

Given J(1,4) and the midpoint is M(2, 1), find the other endpoint K.

Marina CMI [18]

3, if you do the y^2-y^1/x^2-x^1 you will get 3/1 which will be simplified to 3.

6 0

4 years ago

Plz help me find answer. what are the coordinates of slope when y= x/1–x² when dy/dx=1

vova2212 [387]

Step-by-step explanation:

dy/dx

= d/dx [x / (1 - x²)]

= [(1 - x²)(1) - (x)(-2x)] / (1 - x²)²

= (1 + x²) / (1 - x²)².

When dy/dx = 1, (1 + x²) / (1 - x²)² = 1.

=> 1 + x² = 1 - x²

=> 2x² = 0, x = 0.

Also when x = 0, y = (0) / [1 - (0)²] = 0.

Hence the coodinates is (0, 0).

8 0

2 years ago

Divide 150 into 3 parts in the proportion of 4, 6 and 2 1/2 respectively<br><br>

Feliz [49]

Answer:

Hope this helps!!

Step-by-step explanation:

4 = 48

6 = 72

2 $\frac{1}{2}$ = 30

PLZZ MARK BRAINLIEST

5 0

3 years ago

Please Help me!!!

drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

$d=2t^3+5t^2-3$

Displacement at t = 4 hours,

$d(4)=2(4)^3+5(4)^2-3=205\ km$

Velocity of particle is given by :

$v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t$

Velocity at t = 4 hours,

$v=6(4)^2+10(4)=136\ km/h$

Acceleration of the particle is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10$

At t = 4 hours,

$a=12(4)+10=58\ km/h^2$

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0

3 years ago

What is 25% of 167??????

Alborosie

Answer:

41.75

Step-by-step explanation:

<h2><em>Hope this helps and have a nice day :)</em></h2>

6 0

3 years ago

Znajdź wszystkie rozwiązania x^4-16=0​

Znajdź wszystkie rozwiązania x^4-16=0