Segundo o padrão da National Institute of Standards and Technology a alternativa correta é a letra E) 400 músicas. Segundo o padrão disposto acima, dois Giga Bytes equivalem à dois mil Mega Bytes, assim, se cada música tem exatos 5MB, podemos chegar ao total de músicas que podem ser gravadas em um PenDrive de 2GB livres do seguinte modo :
A evolução da microeletrônica possibilitou uma capacidade de armazenamento cada vez maior a cada ano. O desenvolvimento de novas tecnologias na área permite também que os produtores possam produzir músicas, fotos e vídeos com cada vez mais qualidade (consequentemente mais pesada).
<span>C electric power transmisson and electronics</span>
I hope this helps but cars, phones and computers.
The test that a computer needs to pass after a human's conversation with it and not be able to tell if it was a machine or a human is; Turing Test
<h3>Test of Computers</h3>
The correct answer to the blank portion of the question is Turing test. This is because Turing Test is a test of a computer's ability to exhibit intelligent behavior that is equivalent to, or indistinguishable from, that of a human's behavior.
Finally, If the evaluator cannot reliably tell the computer from the human, the machine is said to have passed the test.
Read more about Test of Computer at; brainly.com/question/21283135
Answer:
The program to this question as follows:
Program:
def lettersOnly(s): #defining method lettersOnly
val="" #defining string variable that return value
for i in s: #defining loop to calculate value
if(i.isalpha()): #check condition that value is string
val=val+ i #add value
return val #return value
print(lettersOnly("data3base_ro1c3k5s")) #call method and print value
Output:
databaserocks
Explanation:
In the above python code, a method lettersOnly is declared that accepts a string variable "s" in its parameter. Inside the method, a string variable "val", and loop is declared, in which the "val" variable holds method return value.
- In the loop and if block is used that uses "isalpha" string method, which checks the check alphabetic character in the given value. if this is true it will calculate all value in "val" variable and return its value.
- At the last, the print method is used, which calls the lettersOnly method and prints its return value.
