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alexandr1967 [171]
3 years ago
6

The area of a rectangular field is 1,710 square feet. The length of the field is 45 feet. What is the width of the field.

Mathematics
1 answer:
horsena [70]3 years ago
6 0

Answer:

38 feet

Step-by-step explanation:

area = width × length

width = area ÷ length

1,710 ÷ 45 = 38

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6th grade math help me plzzz
viva [34]

Answer:

The answer is A, B, and D

Step-by-step explanation:

This is really easy, all you have to do is to choose the answers that are less than 1.

Why? because anything less than 1 multiplied by a number gives you a smaller number.

Since C and E are bigger than 1 then they will give you a bigger number than 2/3.

But A, B, and D are less than 1.

So, the answer is A, B, and D

6 0
3 years ago
Read 2 more answers
2 cm green square is painted on a triangle with a base of 6 and a height of 7. A dot will be randomly placed on the triangle. Wh
agasfer [191]
The area of the triangle is
(1/2)*(6)*(7) = 21 cm²

The area of the square is
(2)(2) = 4 cm²

The area of the triangle that is not covered by the square is
21 - 4 = 17 cm²

The probability that the dot will be placed outside the square is
17/21 

Answer: 17/21 (or 0.81)
7 0
3 years ago
If two sides of a triangle measure 12 and 7, which cannot be the perimeter of the triangle?
ser-zykov [4K]
Hi,
Let assume x the 3th side.
x<12+7==> x<19
12<x+7==>x>5
So 5<x<19==> 5+7+12<x+7+12<19+7+12
==>24<x<38
Answer d.

8 0
3 years ago
Please help me with this
kirill [66]

Answer:

15/2 or 7.5

Step-by-step explanation:

5/6 (x + 1/2 + 4)

distribute 5/6 to each number

5/6x + 5/12 + 10/3

change the fraction 10/3 so that it will have the same denominator as 5/12

\frac{10}{3} *4 = 40/12

5/6x + 5/12 + 40/12\\5/6x + 45/12

divide both sides by 5/6

x = 9/2

5/6*9/2+5/12+10/3 = \frac{15}{2}

3 0
1 year ago
A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.
Reptile [31]

Answer:

a.P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}

Step-by-step explanation:

We are given that a linear differential equation

y''+2y=e^{3x}+x^3

We have to find the particular solution

P.I=\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}

P.I=\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}

P.I=\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3

P.I=\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0} (higher order terms can be neglected

P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.Characteristics equation

D^2+2=0

D=\pm\sqrt2 i

C.F=C_1cos \sqrt2x+C_2 sin\sqrt2 x

G.S=C.F+P.I

G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)

3 0
3 years ago
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