G(-3)=<br> this is what I need the value of

Paul is making bread using a recipe. The amount of flour he uses is proportional to the number of loaves of bread. He uses 1114

DiKsa [7]

Answer:

$20

Step-by-step explanation:

Paul is making bread using a recipe. The amount of flour he uses is proportional to the number of loaves of bread. He uses 11 1/4 cups of flour to make 5 loaves of bread. If Paul used 18 cups of flour, and then sold the loaves of bread he made at a bake sale for $2.50 each, how much money would Paul make from his bread sales?

Step 1

Find out how many loaves of bread he can produce from 18 cups of flour

11 1/4 cups of flour = 5 loaves of bread

18 cups of flour = x loaves of bread

Cross Multiply

11 1/4 cups × x loaves = 18 cups × 5 loaves

x loaves = 18 cups × 5 loaves/ 11 1/4 cups

x loaves = 90 ÷ 11 1/4

x loaves = 90 ÷ 45/4

x loaves = 90 × 4/45

x loaves = 8 loaves of bread

He can produce 8 loaves of bread from 18 cups of flour.

Step 2

We are told that:

1 loaf of bread costs $2.50

Hence,

1 loaf of bread = $2.50

8 loaves of bread = $x

Cross Multiply

$x = 8 loaves of bread × $2.50

$x = $20

Therefore, Paul made $20 from his bread sales

8 0

2 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation $A=45e^{-0.05t}$ .

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate $A=15$ and solve for t as:

$15=45e^{-0.05t}$

$\frac{15}{45}=\frac{45e^{-0.05t}}{45}$

$\frac{1}{3}=e^{-0.05t}$

Now we will switch sides:

$e^{-0.05t}=\frac{1}{3}$

Let us take natural log on both sides of equation.

$\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})$

$-0.05t\cdot (1)=\text{ln}(\frac{1}{3})$

$-0.05t=\text{ln}(\frac{1}{3})$

$t=\frac{\text{ln}(\frac{1}{3})}{-0.05}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}$

$t=-\text{ln}(\frac{1}{3})\cdot 20$

$t=-(\text{ln}(1)-\text{ln}(3))\cdot 20$

$t=-(0-\text{ln}(3))\cdot 20$

$t=20\text{ln}(3)$

Therefore, it will take $20\text{ln}(3)$ years for area of the glacier to decrease to 15 square kilo-meters.

6 0

2 years ago

How do i simplify this problem?<br><br>12r+5s-7T+9s-4r

Nimfa-mama [501]

Answer: To simplify this problem you combine the like terms in the equation (numbers with the same variables.)

Demo: 12r + -4r = 8r

4 0

3 years ago

Read 2 more answers

A) Expand and simplify (x + 4)(x-7)<br>

saveliy_v [14]

Answer:

Expanded:x²-7x+4x-28

Simplified: x²-3x-28

Step-by-step explanation:

7 0

3 years ago

I partly know how to do this but I'm still confused. How do I solve this? *Using this response for my other homework problems to

astra-53 [7]

Answer:

its 2/9

Step-by-step explanation:

I remember this from a long time ago but any number repeating that is less than nine is just put over 9, but as it goes up you put it over 99 and so on.

5 0

3 years ago

G(-3)= this is what I need the value of