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Mrac [35]
3 years ago
10

What is the least common denominator for 5,6,and7?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

210

Step-by-step explanation:

5 is a prime number, 6 = 2·3 and 7 is a prime number. Since those number do not have common factors, the least common multiple will be their product:5·6·7 = 210 . Given fractions are already in order from least to greatest.

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Anyone a single pringle and i need help 500 divided by 23 times 3
baherus [9]

Answer:

65.21739130434783

Step-by-step explanation:

5 0
2 years ago
63 is 90% of what number in a number line
lisov135 [29]
If you're trying to say what's 90% of 63, you divide 63 by 10 which is 6.3 then times by 9 which is 56.7
8 0
3 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
No clue what to do for slope , where do i put it ?!!!
Nonamiya [84]
You put the point at (5,0) since it’s rise over run you move 3 up n go 4 to the right
3 0
3 years ago
Solve each of the following literal equations for c: (c/b) - x = 2d and ac + bd = x
maks197457 [2]
(c/b) - x = 2d
(c/b) = 2d + x
c = b(2d + x)
c = 2db + bx

ac + bd = x
ac = x - bd
c = (x - bd) / a OR c = (x/a) - (bd/a)
8 0
3 years ago
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