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Reptile [31]
3 years ago
5

103 + 21 = _ + 103 please help

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
6 0
This is the commutative property of addition. It basically says, x+y=y+x.
To answer your question, 103+21=21+103
garri49 [273]3 years ago
3 0
103 + 21 = Unknown + 103 

Unknown = 21 

21+103
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I neeeeed help please ​
kodGreya [7K]

9514 1404 393

Answer:

  11) C: (a, 4), (b, 3), (c, 2), (d, 1); V: (a, c), (b, d), (4, 2), (3, 1);

     AI: (c, 4), (d, 3); AE: (a, 2), (b, 1); SI: (c, 3), (d, 4); SE: (a, 1), (b, 2)

  12) : C: (a, y), (b, x), (c, w), (d, z); V:(a, c), (b, d), (w, y), (x, z);

     AI: (b, z), (c, y); AE: (a, w), (d, x); SI: (b, y), (c, z); SE: (a, x), (d, w)

Step-by-step explanation:

This is a vocabulary question. It is intended to see if you understand the meaning of the names given to the different angle pairs in this geometry.

All of the pairs of angles filling the first 4 blanks (corresponding, vertical, alt. int., alt. ext.) are congruent pairs of angles. The pairs of angles filling the last two blanks (same-side ...) are supplementary angles (total 180°).

__

<em>Corresponding</em> angles lie in the same direction from the point of intersection. For example, the upper-left angles are corresponding.

<em>Vertical</em> angles are formed from opposite rays.

<em>Alternate</em> refers to angles on opposite sides of the transversal. (<em>Same-side </em>refers to angles on the same side of the transversal. Same-side angles are also called <em>consecutive</em> angles.)

<em>Interior</em> refers to angles that are between the parallel lines. <em>Exterior</em> refers to angles outside the parallel lines.

__

The figures are a bit fuzzy. We assume the angle designations are (CW around the intersection point from upper left, left group first) ...

  Figure 11) {a, b, c, d}, {4, 3, 2, 1}

  Figure 12) {d, c, b, a}, {z, w, x, y}

If this is not correct, you will need to make appropriate substitutions in the pairs given below.

__

11) Corresponding: (a, 4), (b, 3), (c, 2), (d, 1)

  Vertical: (a, c), (b, d), (4, 2), (3, 1)

  Alternate Interior: (c, 4), (d, 3)

  Alternate Exterior: (a, 2), (b, 1)

  Same-side Interior: (c, 3), (d, 4)

  Same-side Exterior: (a, 1), (b, 2)

__

12) Corresponding: (a, y), (b, x), (c, w), (d, z)

  Vertical: (a, c), (b, d), (w, y), (x, z)

  Alternate Interior: (b, z), (c, y)

  Alternate Exterior: (a, w), (d, x)

  Same-side Interior: (b, y), (c, z)

  Same-side Exterior: (a, x), (d, w)

_____

<em>Additional comment</em>

The vocabulary is used to cite various theorems supporting claims regarding angle relationships. In practice, when the lines are parallel, all obtuse angles related to a transversal are congruent, all acute angles are congruent, and the acute angles are supplementary to the obtuse angles. (If the angles are 90°, neither acute nor obtuse, then they are all congruent.)

3 0
2 years ago
Let u,v,wu,v,w be three linearly independent vectors in R7R7. Determine a value of kk, k=k= , so that the set S={u−3v,v−2w,w−ku}
11Alexandr11 [23.1K]

Answer:

1/6

Step-by-step explanation:

For a set of vectors a, b and c to be linearly dependent, the linear combination of the set of vectors must be zero.

C1a + C2b + C3c = 0

From the question, we are given the set S={u−3v,v−2w,w−ku}, the corresponding vectors are a(0, -3, 1), b(-2,1,0) and c(1,0,-k)

The values in parenthesis are the ccoefficients of w, v and u respectively.

On writing this vector as a linear combination, we will have;

C1(0, -3, 1) + C2(-2,1,0) + C3(1,0,-k) = (0,0,0)

0-2C2+C3 = 0........ 1

-3C1+C2 = 0 ........... 2

C1-kC3 = 0 ….......... 3

From equation 2, 3C1 = C2

Substituting into 1, -2(3C1)+C3 = 0

-6C1+C3 = 0

-6C1 = -C3

6C1 = C3.…..4

Substitute 4 into 3 to have

C1-k(6C1) = 0

C1 = k6C1

6k = 1

k = 1/6

Hence the value of k for the set of vectors to be linearly dependent is 1/6

6 0
2 years ago
Which linear equations does the graph show the solution to? Select all that apply. y = 2x + 13 y = –x – 2 y = 3x – 5 y = negativ
salantis [7]

Answer:

y = 2x + 13

y = –x – 2

Step-by-step explanation:

The options are:

y = 2x + 13

y = -x - 2

y = 3x - 5

y= -(1/2)x + 6

y = -2x - 2

The graph is shown in the figure attached. There, point (-5, 3) is shown. Replacing it into the equations we get:

y = 2(-5) + 13  = 3    (so, it is a solution)

y = -(-5) - 2 = 3     (so, it is a solution)

y = 3(-5) - 5  = -20 ≠ 3   (so, it isn't a solution)

y= -(1/2)(-5) + 6  = 8.5 ≠ 3     (so, it isn't a solution)

y = -2(-5) - 2 = 8 ≠ 3     (so, it isn't a solution)

6 0
3 years ago
Read 2 more answers
I only need someone to put it in the quadratic formula I already have solutions. Please answer ASAP!!! I will give brainliest!!!
KengaRu [80]

The quadratic formula is \frac{-b+-\sqrt[2]{b^2-4ac}}{2a}

and in the equation ax^2+bx+c=0

so now all you have to do is substitute the numbers into the quadratic formula

7 0
2 years ago
I went to the movies and bought 4 tickets. It cost me 23 dollars for the tickets after I applied my 5 dollar Tuesday discount. C
Scilla [17]

Answer:

x= 5.75$

Step-by-step explanation:

23 divided by 4 = 5.75$ (without the discount it is 10.75$)

3 0
2 years ago
Read 2 more answers
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