All categories

4 years ago

Please help 20% of 3km = ?

Mathematics

1 answer:

Lorico [155]4 years ago

8 0

20% of 3km is 0.6 Kilometer

You might be interested in

Help asap I'm desperate

ololo11 [35]

The formula or the area of a trapezoid is (a+b) divided by 2 times height so the answer is 128ft2

3 0

3 years ago

Read 2 more answers

Please help me!!!!!!!!!!!!!

monitta

Answer: see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities: tan (A/2) = (sinA)/(1 + cosA)

cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = $\frac{\sqrt2}{2}$

<u>Proof LHS → RHS</u>

Given: $cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o$

Rewrite Fraction: $cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o$

Half-Angle Identity: $\dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}$

Substitute: $\dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}$

Simplify: $\dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}$

$=\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}$

$=\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)$

$=\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}$

$=\dfrac{4}{2}$

= 2

LHS = RHS: 2 = 2 $\checkmark$

7 0

4 years ago

6x+5=53 help me plzzz

aev [14]

Step-by-step explanation:

53-5 is 48

48/6 is 8

X=8

therefore it's 8

4 0

3 years ago

Read 2 more answers

NEED HELP ASAP!!!!!!!!!!

Alona [7]

Answer:

i dont know what your asking

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

MArishka [77]

Answer:

all work is shown and pictured

8 0

3 years ago