The mass of CH₄ that is consumed is 10.598 g.
<h3>What is enthalpy?</h3>
The enthalpy of a system is defined as the sum of the internal energy of a system and the energy that is produced due to its pressure and volume.
It is given by
H = U+PV
The following reaction takes place during the combustion of CH₄
Energy evolved during the combustion, E = 587.9 kJ
Enthalpy of combustion of methane, ∆H = 890.3 kJ
= 587.9 /890
Mass of CH₄ that is consumed = no of moles × molar mass of CH₄
= 587.9 /890 × 16
= 10.598 g
The mass of CH₄ which is consumed is 10.598 g
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Answer : The number of electrons in an atom is, 2 electrons
Explanation :
As we know that there are four quantum numbers which are principle quantum number, azimuthal quantum number, magnetic quantum number and spin magnetic quantum number.
The Principle quantum number, n = 3. That means the electron present in the third energy level.
The Azimuthal quantum number, l = 2. That means the electron present in the d sub-shell.
The magnetic quantum number, . That means it shows the 2 electrons present in one of the five 3d orbitals.
Hence, the number of electrons in an atom is, 2 electrons
Answer:
exothermic process because the process of association of oxygen and hydrogen is taking place..
An oxygen molecule at 25◦C has a speed of 1520 miles/hour.
<h3>Equation :</h3>
As we know
1 km = 1000 meter
So,
678 / 1000 = 0.678 km
And 1 mile = 1.6 km
So,
0.678 / 1.609 = 0.4213 miles
We know that 1 hour = 60×60 = 3600 sec
So,
1 sec = 1 / 3600
= 2.777 x 10⁻⁴ hour
Now finding speed,
speed = distance / time
speed = 0.4213 / 2.777 x 10⁻⁴
speed = 1520 miles/hour
<h3>What is speed ?</h3>
Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words velocity is a vector value, whereas speed is a scalar value.
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The time taken or 25% of the molecules to desorb is 2.2 seconds
<h3>What is a first order reaction?</h3>
A first order reaction is one in which the rate of reaction depends on the concentration of a single specie.
Since;
t1/2 = 0.693/k = 0.693/ 0.128 s-1
t1/2 = 5.4 secs
Using the formula;
0.693/t1/2 = 2.303/t log (No/N)
0.693/5.4 = 2.303/t log 1/0.75
0.693/5.4 = 2.303/t log
0.693/5.4 = 0.287/t
t = 2.2 seconds
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