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lesantik [10]
3 years ago
15

The combustion of hydrogen gas in oxygen, is it an endothermic or exothermic process? Write a chemical reaction for this process

Chemistry
1 answer:
Crank3 years ago
6 0

Answer:

exothermic process because the process of association of oxygen and hydrogen is taking place..

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Question 12 of 32
slavikrds [6]
C
Because I am right
God bless
5 0
2 years ago
Which statement about relative motion is not true?
AURORKA [14]

Explanation:

laws of physics which apply when you are at rest on the earth also apply when you are in any reference frame which is moving at a constant velocity with respect to the earth. For example, you can toss and catch a ball in a moving bus if the motion is in a straight line at constant speed.

7 0
2 years ago
Use a sheet of paper to answer the following question. Take a picture of your answers and attach to this assignment. Draw the st
pentagon [3]

Answer:

Explanation:

Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment

In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.

Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:

keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.

Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.

8 0
3 years ago
Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin
Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

For first-order kinetics, the rate law can be expressed as:

\mathsf{In \dfrac{C}{C_o} = -kt}

Given that:

the rate degradation constant = 0.12 / day

current concentration C = 0.05 mg/L

initial concentration C₀ = 3.65 mg/L

\mathsf{In( \dfrac{0.05}{3.65})= -(0.12) t}

㏑(0.01369863014) = -(0.12) t

-4.29 = -(0.12)

t = -4.29/-0.12

t = 35.75 days

3 0
3 years ago
to checkt the accuracy of a new method, a standard copper alloy containing 23.24%Cu was analyzed and calculated to contain 23.17
tekilochka [14]

Answer:

23.24%_23.17%

10%×1000

10/100×1000=

100

3 0
3 years ago
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