Answer:

Explanation:




= 0.64 kJ/mol = 640 J/mol
R = 8.314 J/mol.K
Using Van't Hoff Equation:








So so sorry if i'm wrong but i'm pretty sure no
Rhenium is a chemical element with the symbol Re and atomic number 75. The electron configuration of Re is [Xe]
.
<h3>
How to write an electronic configuration?</h3>
1. Identify the given element and its atomic number from the periodic table.
2. Write the electron configuration by the energy level and the type of orbital first, then the number of electrons present in the orbital as superscript.
The easiest way to write the electronic configuration for any element is by using a diagonal rule for electron filling order in the different subshells according to the Aufbau principle.
The 3 rules for writing the electron configuration in the orbital box diagram are – the Aufbau rule, the Pauli-exclusion rule, and Hund's Rule.
To learn more about electronic configuration, refer
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Explanation:
The given data is as follows.
Pressure (P) = 170 torr, mass of heptane (m) = 86.7 g
First, we will calculate the number of moles as follows.
No. of moles = 
= 
= 0.867 mol
Now, the number of moles of
are calculated as follows.
No. of moles = 
=
= 1.07
Therefore, mole fraction of heptane will be calculated as follows.
Mole fraction =
= 
= 
= 0.445
Now, we will calculate the partial pressure of heptane as follows.

=
= 75.65 torr
Thus, we can conclude that the partial pressure of heptane vapor above this solution is 75.65 torr.
Answer:
Ka = 4.76108
Explanation:
- CO(g) + 2H2(g) ↔ CH3OH(g)
∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]
[ ]initial change [ ]eq
CO(g) 0.27 M 0.27 - x 0.27 - x
H2(g) 0.49 M 0.49 - x 0.49 - x
CH3OH(g) 0 0 + x x = 0.11 M
replacing in Ka:
⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)
⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)
⇒ Ka = (0.11) / (0.38)²(0.16)
⇒ Ka = 4.76108