Question

If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it? (Hint: Use MsVs = MdVd to find the amount of concentrated solution you need, then add water to reach 100 mL.) Show your work.

Answer 1

Answer: We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.

Explanation:

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 0.2 M

$V_1$ = volume of stock solution = 100 ml

$M_2$ = molarity of resulting solution = 1.0 M

$V_2$ = volume of resulting solution = ?

Now put all the given values in the above law, we get the volume of resulting solution.

$(0.2M)\times 100=(1.0M)\times (V_2)$

$V_2=20ml$

Therefore, the volume of 1.0 M required is 20 ml.

We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.