Answer:
no
Explanation:
this answer is because there is no oxygen on the moob
Answer:
4.13 moles of Fe
Explanation:
Step 1: Write the balanced equation
3 CO + Fe₂O₃ ⇒ 2 Fe + 3 CO₂
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of CO to Fe is 3:2.
Step 3: Calculate the moles of Fe formed from 6.20 moles of CO
We will use the previously established molar ratio.
6.20 mol CO × 2 mol Fe/3 mol CO = 4.13 mol Fe
The answer to this question is false
Answer:
25.0 mol O₂ are required in the second reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
4NH₃ (g) + 5O₂ (g) → 4NO (g) + 6 H₂O(l)
Molar ratio in first reaction is 1:2
For every mol of N₂. I make 2 moles of ammonia. If I have 20 moles of N₂, i'm going to get, 40 moles of ammonia.
In the second reaction, molar ratio between products is 4:5.
If I obtained 40 moles of ammonia in first step, let's prepare the rule of three.
4 moles of ammonia react with 5 moles of O₂
40 moles of ammonia react with ( 40.5) /4 = 25moles
Currently in this equation, you have 2 hydrogen atoms and 2 oxygen atoms on the left, and then 2 hydrogen atoms and 1 oxygen atom on the right. To balance, you would need to even out the oxygens, so we can first place a 2 in front of H2O to get:
H2 + O2 -> 2H2O
Now, however, you can see that we have too many hydrogen atoms on the right, so to get the final answer, we add a 2 in front of hydrogen on the left:
2H2 + O2 -> 2H2O
I hope this helps!
