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Fiesta28 [93]
3 years ago
10

Please follow meWhat is science ?​

Chemistry
1 answer:
bonufazy [111]3 years ago
6 0
<h2>Explanation:</h2><h3>the intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment. </h3>

<h3>"the world of science and technology"</h3><h3>Similar:</h3><h3>branch of knowledge</h3><h3>area of study</h3><h3>discipline</h3><h3>field</h3><h3>a particular area of science.</h3><h3>plural noun: sciences</h3><h3>"veterinary science"</h3><h3>a systematically organized body of knowledge on a particular subject.</h3><h3>"the science of criminology" </h3>

<h3>Translations and more definitions</h3><h3>Learn new words</h3><h3>Which word is similar to science?</h3><h3>Discipline</h3><h3>or</h3><h3>Discussion</h3><h3>Question 1 of 5</h3><h3>Feedback</h3>

<h3>Science, any system of knowledge that is concerned with the physical world and its phenomena and that entails unbiased observations and systematic experimentation. ... In general, a science involves a pursuit of knowledge covering general truths or the operations of fundamental laws. </h3>

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Imagine a planet that has a similar atmospheric pressure to Earth (760 mmHg) but different concentrations of gases in its atmosp
RUDIKE [14]

Answer:

76 mmHg is the partial pressure of oxygen on this new planet.

Explanation:

Atmospheric pressure on air on earth = 760 mmHg

On an unknown planet :

Oxygen makes up 10% of the atmosphere.

The mole fraction of oxygen gas can be written as = \chi_1=\frac{10}{100}=0.1

Carbon dioxide makes up 15% of the atmosphere.

The mole fraction of carbon dioxide gas can be written as = \chi_2=\frac{15}{100}=0.15

Nitrogen makes up the remaining 75% of the atmosphere.

The mole fraction of nitrogen gas can be written as = \chi_1=\frac{75}{100}=0.75

Atmospheric pressure of air on unknown planet,p= 760 mmHg (given)

Partial pressure of gases can be calculated by the help o Dalton's law of partial pressure:

Partial pressure of oxygen gas :

p_1=p\times \chi_1

p_1=760 mmHg\times 0.1=76 mmHg

Partial pressure of carbon dioxide gas :

p_2=p\times \chi_2

p_2=760 mmHg\times 0.15=114 mmHg

Partial pressure of nitrogen gas :

p_3=p\times \chi_3

p_3=760 mmHg\times 0.75=570 mmHg

8 0
3 years ago
Denise owns a car that runs on a mixture of gasoline and ethanol. She can buy fuels that have 85% ethanol or 25% ethanol. How mu
Hunter-Best [27]
<span>85% ethanol | 25% ethanol | 50% ethanol
x | y | 20 gal

use x and y because you don;t know how much she needs.

0.85x | 0.25y | 20(0.5)

85% is 85/100 or 0.85, and you need that much of x, same goes for the 25% and 50% mixtures so now you can make up 2 equations
1) x + y = 20 2) 0.85x + 0.25y= 10 (you get 10 when you multiply 20 by 0.5) now you can solve for x or y using substitution.
first rewrite 1) in terms of x or y: x+ y= 20 ----> y= 20 - x now you can substitute 20- x for y in the second equation.. 0.85x + 0.25y= 10 0.85x + 0.25(20-x)= 10 distribute here..(0.25 * 20 and 0.25 * (-x) ) 0.85x + 5 - 0.25x = 10 combine like terms 0.6x +5 = 10 move the 5 over to the other side 0.6x= 10 -5 0.6x = 5 divide both sides by 0.6 x= 25/3 or 8.3 now you know the amount of x so you can substitue this back into the first equation to find y. 0.85x + 0.25y= 10 0.85(25/3) +0.25y= 10 85/12 + 0.25y= 10 0.25y = 10- 85/12 0.25y= 35/12 y= 35/3 or 11.6 you can check by putting these values into the euations: 1) x+ y= 20 25/3 + 35/3 =20 20= 20 good so far 2) 0.85x + 0.25y= 10 0.85(25/3) + 0.25(35/3)=10 10 = 10

so our values for x and y work
x= 25/3 and y= 35/3</span>
5 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPP MEEHHHHHHHHHHHHHH
AnnZ [28]
Here you are looking on the Free Body diagram of a net force of 0N in both the x and y-directions.  the only ones that has that condition met is A and C.
4 0
3 years ago
What is the boiling point of 0.464 m lactose in water? (Kb of water = 0.512 oC/m). Enter your answer to 3 decimal places.
kirill [66]

Answer:

Boiling point for the solution is 100.237°C

Explanation:

We must apply colligative property of boiling point elevation

T° boiling solution - T° boiling pure solvent = Kb . m

m = molalilty (a given data)

Kb = Ebulloscopic constant (a given data)

We know that water boils at 100°C so let's replace the information in the formula.

T° boiling solution - 100°C = 0.512 °C/m . 0.464 m

T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C

3 0
3 years ago
Consider two gases, A and B, are in a container at room temperature. What effect will the following changes have on the rate of
KengaRu [80]

Answer:

i think it will increase the rate of chemical reaction as pressure is directly proportional to the reactivity of gas.

8 0
3 years ago
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