Answer:
After replication, identical copy of the Double stranded DNA is produced. Complementary strand for each of stand given below is
Explanation:
1. AACGTACGATCGATGCACATGCATGGCTACGC
Complementary strand
TTGCATGCTAGCTACGTGTACGTACCGATGCG
Protein encode: NVRSMHMHGY
2. CCCGGGTATGCATGTACGTACGTCGTATATCG
Complementary strand
GGGCCCATACGTACATGCATGCAGCATATAGC
Protein encode: PGYACTYVVY
3. CGCGATCGAGCGATCGACGAATGCCTAGTTTT
Complementary strand
GCGCTAGCTCGCTAGCTGCTTACGGATCAAAA
Protein encode: RDRAIDECLV
4. TTAAACGAGCTGCTAGCTATTTTTAAAACCCCG
Complementary strand
AATTTGCTCGACGATCGATAAAAATTTTGGGGC
Protein encode: LNELLAIFKTP
Answer:
<u> The following four traits are -: </u>
- <u>Pedigree 1 -</u> A recessive trait (autosomal recessive) is expressed by pedigree 1.
- <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
- <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
- <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.
Explanation:
<u>Explaination of each pedigree chart</u>-
- Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected.
In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa) - <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (
) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical
must be contributed by II-6. - The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
- <u>Pedigree 4</u> is an <u>X-linked dominant function</u> characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.
In the question the pedigree chart was missing ,hence it is given below.
Answer:
Most DNA is located in the cell nucleus (where it is called nuclear DNA), but a small amount of DNA can also be found in the mitochondria (where it is called mitochondrial DNA or mtDNA). Mitochondria are structures within cells that convert the energy from food into a form that cells can use.
Explanation:
Answer: Dr. Balduzzi says it's important to remember that sweat is your body's main evaporative cooling system -- kind of like an internal fan. If you're exercising in cold air, your body doesn't need to produce as much sweat to keep you cool.
Explanation: