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3 years ago

4523000 scientific notation

Mathematics

1 answer:

bearhunter [10]3 years ago

6 0

Answer:

4523 x 10 to the 3rd power

Step-by-step explanation:

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What is the radius and diameter of the following circle?

belka [17]

Answer:

Radius = 5.1

Diameter = 10.2

Step-by-step explanation:

Radius is a straight line that connects the center of a circle to a point on the circumference (outside of the circle).

Diameter is a straight line that goes through the center of a circle and connects two points on the circumference (outside of the circle).

The line shown goes from the center to the outside of the circle, so it is the radius

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4 years ago

If matrix A is of the size 2×3 and we are able to add matrix B to A. what must be the size of B be?

tankabanditka [31]

Answer:

6 be because 2×3 =6 so B it will be the given answer

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3 years ago

at a sale, dresses were sold for $10 each. if the dresses originally cost $200 each, what percentage of its original price was a

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

10/200 = .05

.05 = 5%

7 0

3 years ago

Read 2 more answers

Find the missing side round your answer to the nearest tenth

kap26 [50]

Use trigonometric ratios.
Use angle(19)
Adjacent side of angle measure 19 is X
The hypotenuse is 21.
Use the cosine
Cos(19)=x/21

Plug in calculator
(21)cos(19)=19.85

Round to the nearest tenth. Which means the 8 rounds up to 9.

Answer: 19.9

7 0

3 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: