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kiruha [24]
3 years ago
6

Find the 8th term in the sequence: x + 1, 2x + 1, 3x + 1,...

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
The common difference is x

the first term is x+1

a_8 = x+1 + x(8-1) = x+1 + 7x = 8x + 1

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For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp
Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

Expected value of days = np = \frac{1}{365^2}

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0
3 years ago
Help please help me please
allsm [11]

Answer:

A. 2 (0)=0

B. 2 (2)=4

Step-by-step explanation:

You have to multiply the X numbers by 2 for example 2x , x=2 , 2x2=4

8 0
2 years ago
Can you solve this problem please​
Afina-wow [57]

Answer:

k = 11

Step-by-step explanation:

Given the points are collinear then the slopes between consecutive points are equal.

Using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (1, - 1)

m = \frac{-1-1}{1-5} = \frac{-2}{-4} = \frac{1}{2}

Repeat with another 2 points and equate to \frac{1}{2}

with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (k, 4)

m = \frac{4+1}{k-1} , then

\frac{5}{k-1} = \frac{1}{2} ( cross- multiply )

k - 1 = 10 ( add 1 to both sides )

k = 11

6 0
3 years ago
Read 2 more answers
Solve for y. <br> 2x+6y=12
Veronika [31]
2x + 6y = 12

2x - 2x + 6y = 12 - 2x

6y = 12 - 2x

6y/6 = 12/6 - 2x/6

Y = 2 - 2/6 X

Y = 2 - 1/3 X or

Y = -1/3 X + 2.
7 0
3 years ago
Please help with this
ioda

Answer:

Some have multiple choices. See below for additional comments.

  • a) iii
  • b) i
  • c) v
  • d) ii
  • e) iv

Step-by-step explanation:

i -- slope-intercept form. Shows the slope and the y-intercept

ii -- slope-intercept form. Shows the slope and the x-intercept

iii -- intercept form. Shows both the x- and y-intercepts

iv -- standard form.

v -- point-slope form. Shows the slope and one point on the line.

vi -- another point-slope form. Shows the slope and one point on the line

__

With the above forms in mind, ...

a) both intercepts are best shown in form iii

b) the slope is shown in forms i, ii, v, vi. Form i is the most uncluttered.

c) points are shown in forms v and vi. Form v may be least confusing.

d) the sign can be readily determined in form ii.

e) testing the given point is easily done using forms ii and iv. Form iv may be the best for this.

_____

<em>Additional comments</em>

Since each of these forms of the equation has utility in different situations, it can be worthwhile to learn the different forms. For example, I like the standard form for making perpendicular lines, though any of the "slope-" forms can be useful for that, too. The useful form to start with will be the one that best relates to the information given. (For two points given, there is a "2-point form" not shown here.)

6 0
3 years ago
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