36 all together.
22 first
14 second
8 random chosen
A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29
Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)
B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29
Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)
C) 22/36
21/35
20/34
19/33
18/32
17/31
Multiply..
Probability.. 0.038306451612903
D) 14/36
13/35
12/34
11/33
X... p=0.016993464052288
Probably not correct, haven't done probability in years.
Answer: D.
Step-by-step explanation: you find the ratio of the other lengths, then apply that ratio to the length of DC. Pls mark as brainliest?
Answer:
b^2 + 3b - 4 + 4/(b-2)
Step-by-step explanation:
see pic
