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2 answers:
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The <span>given the piecewise function is :
</span>
![f(x) = \[ \begin{cases} 2x & x \ \textless \ 1 \\ 5 & x=1 \\ x^2 & x\ \textgreater \ 1 \end{cases} \]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5C%5B%20%5Cbegin%7Bcases%7D%20%0A%20%20%20%20%20%202x%20%26%20x%20%5C%20%5Ctextless%20%5C%20%201%20%5C%5C%0A%20%20%20%20%20%205%20%26%20x%3D1%20%5C%5C%0A%20%20%20%20%20%20x%5E2%20%26%20x%5C%20%5Ctextgreater%20%5C%201%20%0A%20%20%20%5Cend%7Bcases%7D%0A%5C%5D)
To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25
To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4
To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4
To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
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So, the statements which are true:<span>
</span><span></span>
</span>
To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25
To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4
To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4
To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
================================
So, the statements which are true:<span>
Answer:
D). 6 3/4
Step-by-step explanation:
Given,
The three eggs with the heaviest weights are;
ounces
ounces, &
2 ounces
To find,
The total weight of the three heaviest eggs = ounces +
ounces + 2 ounces
= 5/2 + 9/4 + 2/1
Taking the L.C.M. of 2, 4, and 1,
= 10/4 + 9/4 + 8/4
= (10 + 9 + 8)/4
= 27/4 or 6 3/4
The idea for transitions for an equation like this is
where m = slope
h = how much left or right (note the negative)
k = how much up or down
moving 13 down would mean
k = -13
so
D. would be your answer
where m = slope
h = how much left or right (note the negative)
k = how much up or down
moving 13 down would mean
k = -13
so
D. would be your answer