The best way to compare the two would be median and Ian generally gets more.
He sells it at $80 which gives him a profit of $5!
Answer:
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8)</span></span></span></span>
Explanation:
write as : <span>y=50000<span><span>(0.8)</span>x</span></span>
Taking logs:
<span><span>log<span>(y)</span></span>=<span>log<span>(50000)</span></span>+<span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span></span>
But <span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span> is the same as <span>x<span>log<span>(0.8)</span></span></span>
Thus
<span>x=<span><span><span>log<span>(y)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
</span></span></span></span></span>Now swap the x'x and the y's giving:<span><span><span><span><span>
</span></span></span></span></span>
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
my teacher helped a little bit
</span></span></span></span></span>
Answer:
288
Step-by-step explanation:
1. Subtract 14.95 from 253.99
2. Then you are going to divide 239.04 by 0.83
3. Your answer will be 288
The solution would be like
this for this specific problem:
<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫
0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [
-2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [
2·r² ] dr </span>
<span>=
(2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>
So the volume of the
given solid is 16/3. I am hoping that these answers have satisfied
your query and it will be able to help you in your endeavors, and if you would
like, feel free to ask another question.
