3 years ago

X over 3 equals 1 over 4. how do i solve this in algebra? its solving one-step equations.

Mathematics

1 answer:

Snezhnost [94]3 years ago

6 0

Cross multiply X×4=3×1 4x=3 X= 3/4

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Find the output, k, when the input, t, is -7<br><br> K = 10t - 19 <br><br> K= ?

Katarina [22]

Answer:

k= -89

Step-by-step explanation:

k = 10t - 19 and t = -7

k=10 (-7) - 19

k= -70 - 19

k= -89

3 0

3 years ago

Determine the slope and the y-intercept of the line represented by the equation y= -7/3×+3 slope: 7/9 ;y-intercept: 3 slope: 9/7

Mademuasel [1]

Answer:

$slope ⟹ \: - \frac{7}{9} \\ y \: intercept⟹ \: 3$

Step-by-step explanation:

The standard form of this equation is

$y = mx + c \\$

m stands for the gradient or the slope, and c represents the y-intercept

$y = mx + c \\ y = - \frac{7}{9} x + 3 \\ m = - \frac{7}{9} \: \\ and \: \\ \: y \: intercept \: = 3$

7 0

2 years ago

Need help immediately

Tanzania [10]

Answer:

52,5°

Step-by-step explanation:

0,5 × (135 - 30)

= 0,5 × (105)

= 52,5°

7 0

3 years ago

2(5m^4n^-1)^3 simplify show work please

dangina [55]

Answer:

$\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}$

Step-by-step explanation:

$\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}$

8 0

3 years ago

Is 14/21 proportional

pantera1 [17]

Answer

Yes

both divide by 7

2/3

Step-by-step explanation:

Another example if it was 15/10

Then yes

Both divide by 5

3/2

8 0

2 years ago

Read 2 more answers