What words can you spell out of the periodic table

An unstretched spring has a length of 10. centimeters. When the spring is stretched by a force of 16 newtons, its length is incr

Fed [463]

Answer:

The spring constant of this spring is 200 N/m.

Explanation:

Given:

Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]

Stretched length of the spring (x₁) = 18 cm = 0.18 cm

Force acting on the spring (F) = 16 N

Spring constant of the spring (k) = ?

First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.

So, Change in length = Final length - Initial length

$\Delta x = x_1-x_0=0.18-0.10=0.08\ m$

Now, restoring force acting on the spring is directly related to its elongation or compression as:

$F=k\Delta x$

Rewriting in terms of 'k', we get:

$k=\dfrac{F}{\Delta x}$

Now, plug in the given values and solve for 'k'. This gives,

$k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m$

Therefore, the spring constant of this spring is 200 N/m.

5 0

3 years ago

A person kicks a ball, giving it an initial velocity of 20.0 m/s up a wooden ramp. When the ball reaches the top, it becomes air

Alex Ar [27]

Answer:

(a) Height is 4.47 m

(b) Height is 4.37 m

Solution:

As per the question:

Initial velocity of teh ball, $v_{o} = 20.0 m/s$

Angle made by the ramp, $\theta = 22.0^{\circ}$

Distance traveled by the ball on the ramp, d = 5.00 m

Now,

(a) At any point on the projectile before attaining maximum height, the velocity can be given by the eqn-3 of motion:

$v^{2} = v_{o}^{2} - 2gH$

where

H = $dsin22^{\circ} = 5sin22^{\circ}$

g = $9.8 m/s^{2}$

$v^{2} = 20^{2} - 2\times 9.8\times 5sin22^{\circ}$

$v = \sqrt{400 - 19.6\times 5sin22^{\circ}}$ = 19.06 m/s

Now, maximum height attained is given by:

$h = \frac{(vsin\theta)^{2}}{2g}$

$h = \frac{(19sin(22^{\circ}))^{2}}{2\times 9.8} = 2.60 m$

Height from the ground = $5sin22^{circ} + 2.86 = 1.87 + 2.60 = 4.47m$

(b) now, considering the coefficient of friction bhetween ramp and the ball, $\mu = 0.150$ :

velocity can be given by the eqn-3 of motion:

$v^{2} = v_{o}^{2} - 2gH - \mu gd$

$v^{2} = 20^{2} - 2\times 9.8\times 5sin22^{\circ} - 0.150\times 9.8\times 5$

$v = \sqrt{400 - 19.6\times 5sin22^{\circ} - 0.150\times 9.8\times 5}$ = 18.7 m/s

Now, maximum height attained is given by:

$h = \frac{(vsin\theta)^{2}}{2g}$

$h = \frac{(18.7sin(22^{\circ}))^{2}}{2\times 9.8} = 2.50 m$

Height from the ground = $5sin22^{circ} + 2.86 = 1.87 + 2.50 = 4.37 m$

6 0

3 years ago

A proton with a speed of 3.2 x 106 m/s is shot into a region between two plates that are separated by a distance of 0.23 m. As t

harina [27]

Answer:

<h2>The magnitude of the magnetic is 0.145 T</h2>

Explanation:

Given :

Speed of proton $v = 3.2 \times 10^{6}\frac{m}{s}$

Mass of proton $m = 1.67 \times 10^{-27}$ Kg

The force on the proton in magnetic field is given by,

$F = q (v \times B)$

$F = qvB \sin \theta$

But $\sin 90 = 1$ (∵ Force is perpendicular to the velocity so $\theta = 90$ )

$F = qvB$

When particle enter in magnetic field at the angle of 90° so particle moves in circle

So force is given by,

$F = \frac{mv^{2} }{r}$

Where $r =$ radius but in our case 0.23 m, $q = 1.6 \times 10^{-19}$ C

By comparing above two equation,

$B = \frac{mv}{qr}$

$B = \frac{1.67 \times 10^{-27} \times 3.2 \times 10^{6} }{1.6 \times 10^{-19} \times 0.23 }$

$B = 0.145$ T

5 0

3 years ago

If a lawn mower is pushed with a distance of 30 meters and 12N-m of work is exerted, calculate the force.

Nimfa-mama [501]

Answer:

Explanation:

W = FΔx so filling in:

12 = F(30) so

F = .4N

7 0

3 years ago

What does it mean to say that a wave is a cyclic, or periodic, disturbance

Ivenika [448]

Wave is a disturbance or energy that propagate through medium from one point to other point

So basically it is a flowing energy that flows into the medium and hence medium particles start oscillating about their mean position to and fro.

This motion of medium particles or this to and fro motion is about their mean position and this will always be cyclic or periodic motion

This means the disturbance or energy continuously flow through the medium such that it will change the position of medium particle and this will be cyclic in order

For an example

$y = A sin(\omega t + kx + \phi)$

so here above equation of wave is a travelling wave in which displacement of medium particle from its mean position is given by "y"

Now we can see that this disturbance depends upon the sine function and it will repeat its same position after every 2 pi time interval as it is cyclic function for this value

Due to this phenomenon of repeatation of its same position we can say that it is disturbance of wave is cyclic.

3 0

3 years ago