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Viefleur [7K]
3 years ago
12

Help uhh i need to know this answer

Physics
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

Explanation:

2. 330.63 ft because v*t=d and 3.09*107=330.63

3. 4.2 because 10/2.4=4.1666

4. 130 miles because 2 hours times 65mph= 130

5. 62.3 seconds because 480000/7700=62.33766233

8. 60 meters, because 0.5 *120 (because 2 minutes converted to seconds is 120) is equal to 60.

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A frictionless cart of mass M is attached to a spring with spring constant k. When the cart is displaced 6 cm from its rest posi
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Answer:

Time period of horizontal Oscillation  = T = 2\pi\sqrt{\frac{m}{k} }

As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.

Explanation:

Solution:

As we know that:

F = Kx

Here,

K = Spring constant

x = displacement.

First, they are displacing it with 6 cm from its rest position for which Time period of the oscillation is T = 2 seconds.

But next, they want to know the effect on the time period of the oscillation if the displacement x is doubled from 6cm to 12 cm.

First of all, let us see the equation of the time period of the oscillation.

We need to check, if time period does depend on the displacement or not.

As we know,

Time period of horizontal Oscillation  = T = 2\pi\sqrt{\frac{m}{k} }

As you can see, from the equation, Period of oscillation depends upon the mass and the spring constant. Not on the displacement.

Since, K is the constant for a particular spring, we need to change the mass of the cart to change the time period.

Hence the Time period will remain same.

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