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3 years ago

Atoms are happy (they will not readily react with other elements) when they have a full outside ring of

Physics

1 answer:

Len [333]3 years ago

7 0

Answer: TRUE

Explanation:

Atoms are happy when they will not react with other elements while having a full outside ring of electrons because this makes them to be noble.

A stable atom possesses full outside ring of electrons while unstable one does not. So, they are happy also because of stability.

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What is dispersion of light?

algol13

Answer:

$\huge \bold \blue{ \underline{ answer}}$

The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.

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2 years ago

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Calculate the centripetal force acting on a 925 kg car as it rounds an unbanked curve with a radius of 75 m at a speed of 22 m/s

igomit [66]

Since f=m(v^2/r),or fnet is equal to ma.

force = unknown
velocity=22m/s
radius=75m

f=m(v^2/r)
f=925(22^2/75)
f=5969.333N

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3 years ago

Section 2.2

Feliz [49]

Answer:

Speed changes at the rate of 24 m/s for each second over time.

Explanation:

We are told the object's acceleration is equal to 24 m/s²

Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.

Thus, we can rephrase the acceleration in this question to mean;

Speed changes at the rate of 24 m/s for every second with time.

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3 years ago

A thermogram identifies the warm and cool parts of an object by using

andrew11 [14]

Infrared rays are used in many forms of thermal technology. This is also used in weather reports to find the temperature of the surrounding areas.

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4 years ago

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Late one night on a highway, a car speeds by you and fadesinto the distance. Under these conditions the pupils of your eyes(aver

Andrews [41]

Answer:

10432.19076 m

Explanation:

$\lambda$ = Wavelength = 660 nm

d = Diameter of pupils = 6 mm

s = Distance between lights = 1.4 m

L = Distance from observer

From Rayleigh's criteria we have

$1.22\lambda=dsin\theta$

As $\theta$ is small $sin\theta=\dfrac{s}{L}$

So, the equation becomes

$1.22\lambda=d\dfrac{s}{L}\\\Rightarrow L=\dfrac{ds}{1.22\lambda}\\\Rightarrow L=\dfrac{6\times 10^{-3}\times 1.4}{1.22\times 660\times 10^{-9}}\\\Rightarrow L=10432.19076\ m$

The car is 10432.19076 m from me

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4 years ago