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olasank [31]
2 years ago
9

Who are people that you can go to for help name three?

Physics
2 answers:
ycow [4]2 years ago
8 0

Answer:

Close friends, police, teachers

Explanation:

joja [24]2 years ago
6 0

Answer:

parent

teacher

peer

Explanation:

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If wavelength and speed of a wave are 4 m and 332 m/s respectively, calculate its frequency<br>​
Furkat [3]

Explanation:

<em>Given </em>

<em>wavelength </em><em>=</em><em> </em><em>4</em><em> </em><em>m</em>

<em>speed </em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em> </em><em>m/</em><em>s</em>

<em>frequency </em><em>=</em><em> </em><em>?</em>

<em>We </em><em>know </em><em>we </em><em>have </em><em>the </em><em>formula </em>

<em>wavelength</em><em> </em><em>=</em><em> </em><em>speed </em><em>/</em><em> </em><em>frequency </em>

<em>4</em><em> </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em> </em><em>/</em><em> </em><em>frequency </em>

<em>frequency </em><em>=</em><em> </em><em>3</em><em>3</em><em>2</em><em>/</em><em>4</em>

<em>Therefore </em><em> </em><em>frequency </em><em>is </em><em>8</em><em>3</em><em> </em><em>Hertz </em><em>.</em>

4 0
2 years ago
What happens when you want to move the boat forward? You pull the oars toward yourself.Explain why you do this.
vampirchik [111]

Answer:

You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.

8 0
2 years ago
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Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the
Zolol [24]

Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

A) 0.10 kg is lightest among them, so it's your answer

6 0
3 years ago
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Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

7 0
2 years ago
Optimal cardiorespiratory fitness requires a BMI of __________.
PtichkaEL [24]

Answer:

A. 18.5 to 24.9

Explanation:

5 0
2 years ago
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