Ask question

Ask question

All categories

3 years ago

8

A 2.0 kg stone is tied to a 0.30 m string and swung around a circle at a constant angular velocity of 12.0 rad/s. The net torque

on the stone about the center of the circle is?

1 answer:

saul85 [17]3 years ago

6 0

Answer: τ = 0

Explanation:

At constant angular velocity there is no angular acceleration therefore no torque.

τ = Iα

You might be interested in

Lionel makes a graphic organizer to compare the electric field around a positive charge with the electric field around a negativ

krek1111 [17]

X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge

6 0

3 years ago

Read 2 more answers

A 55-kg woman is wearing high heels.

Grace [21]

Answer:

Pressure, $P=1.90\times 10^7\ Pa$

Explanation:

It is given that,

Mass of the woman, m = 55 kg

Diameter of the circular cross section, d = 6 mm

Radius, r = 3 mm = 0.003 m

Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :

$P=\dfrac{F}{A}$

$P=\dfrac{mg}{\pi r^2}$

$P=\dfrac{55\times 9.8}{\pi (0.003)^2}$

$P=1.90\times 10^7\ Pa$

So, the pressure exerted on the floor is $1.90\times 10^7\ Pa$ . Hence, this is the required solution.

7 0

3 years ago

The objective lens in a DVD player must move quickly to keep the laser beam focused on the disc's reflective layer. Why must thi

Zinaida [17]

Explanation:

The small mass of lens in a DVD player accounts for small inertia of the lens. Hence, even on application of force of small magnitude, the lens is rapidly accelerated. Moreover, the small mass of lens also accounts for lower resistance to change in its motion and therefore, again can be rapidly accelerated back and forth.

4 0

3 years ago

Big Bob is on his Harley and moving at 14.0m/s. He then accelerates to a velocity of 25m/s over a distance of 0.250 km. What is

Xelga [282]

As we know that it has all given data given as

$v_i = 14 m/s$

$v_f = 25 m/s$

distance moved = 0.250 km = 250 m

now we can use kinematics to find acceleration

$v_f^2 - v_i^2 = 2 a d$

$25^2 - 14^2 = 2 * a * 250$

$a = 0.86 m/s^2$

so it will accelerate at rate of 0.86 m/s^2

8 0

3 years ago

You have a large flashlight that takes 4 D-cell batteries, each with a voltage of 1.5 volts. If the current in the flashlight is

Naddik [55]

Ohm's law states that,
V = I x R
where V, I, and R are voltage, current, and resistance, respectively. Rearranging the equation gives,
R = V / I
Replacing the variables with the given values,
R = 1.5 volts / 2.0 amp
The answer is letter B. 0.75 ohms.

3 0

3 years ago

Read 2 more answers