Answer:
Work done by the frictional force is 
Explanation:
It is given that,
Mass of the car, m = 1000 kg
Initial velocity of car, u = 26.1 m/s
Finally, it comes to rest, v = 0
We have to find the work done by the frictional forces. Work done is equal to the change in kinetic energy as per work - energy theorem i.e.
W = −340605 J
or
Hence, the correct option is (a).
Explanation:
a) The rope obeys Hooke's law, so:
F = k Δx
The elastic energy in the rope is:
EE = ½ k Δx²
Or, in terms of F:
EE = ½ F Δx
Use trigonometry to find the stretched length.
cos 20° = 35 / x
x = 37.25
So the displacement is:
Δx = 37.25 − 24
Δx = 13.25
The elastic energy per rope is:
EE = ½ (3.7×10⁴ N) (13.25 m)
EE = 245,000 J
There's two ropes, so the total energy is:
2EE = 490,000 J
Rounded to one significant figure, the elastic energy is 5×10⁵ J.
b) The elastic energy in the ropes is converted to gravitational energy.
EE = PE = mgh
5×10⁵ J = (1.2×10³ kg) (9.8 m/s²) h
h = 42 m
Rounded to one significant figure, the height is 40 m. So the claim is not justified.
Inertia is the name. Inertia is when a moving object stays in motion unless stopped by an outside force. This is Newton’s first law of motion
The function y must be equal to 0 on any interval on which it is defined. The function y must be increasing (or equal to 0) on any interval on which it is defined.
Analysis of solution by seeing differential equation:
Given differential equation is: y' = (1/2)y2
How do deduce the results just by seeing them?
The equation tells us that:
rate = positive of ( y^2 )
rate = positive of (positive or zero) = positive or zero
Thus, the rate is positive or zero no matter what value we put in the place of y from its valid domain, since.
When the rate is positive or zero, that means the function will never grow upwards. Thus, either increasing or staying at the same level.
Learn more about differential equations here:
brainly.com/question/25731911
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