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kodGreya [7K]
3 years ago
12

Given the following Venn diagram find M n N

Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0
The answer would be (4,7)

M n N means M and N so you write all the numbers inside the intersect of M and N.
Ksju [112]3 years ago
4 0

Answer:

M∩N={4,7}

Step-by-step explanation:

Intersection(∩) of two sets is the set of all those elements which are common in both.

M={4,7,9,3}

N={4,7,6}

Since, M and N have 4 and 7 in common

Hence, M∩N={4,7}

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What is the solution to the system of equations <br><br> 3x+2y=39<br> 5x-y=13
Vadim26 [7]

Hiya. I'm going to rewrite the second equation.

By subtracting 5x by both sides, I'll be able to have y by itself:

-y=-5x+13

I'm going to then divide both sides by -1 to get:

y=5x-13.


Then, I'm going to plug that equation into the first equation

3x+2(5x-13)=39

Factor:

3x+10x-26=39

Combine like terms:

13x=65

Divide both sides by 13 to get x by itself to get x=5


Plug this back into the equation of y=5x-13

y=5(5)-13 to get y=12

4 0
3 years ago
Read 2 more answers
(18 x 4) * 5 =<br> 22 x (6 x 10) =<br> 15 x (4 x 20) =
zhenek [66]

Answer:

(18 x 4) * 5 = 360

(18 x 4) * 5 = 1320

15 x (4 x 20) = 1200

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A 99% confidence interval for the difference between two proportions was estimated at 0.11, 0.39. Based on this, we can conclude
sladkih [1.3K]

Answer:

\hat p_1 -\hat p_2 \pm z_{\alpha/2} SE

And for this case the confidence interval is given by:

0.11 \leq p_1 -p_2 \leq 0.39

Since the confidenc einterval not contains the value 0 we can conclude that we have significant difference between the two population proportion of interest 1% of significance given. So then we can't conclude that the two proportions are equal

Step-by-step explanation:

Let p1 and p2 the population proportions of interest and let \hat p_1 and \hat p_2 the estimators for the proportions we know that the confidence interval for the difference of proportions is given by this formula:

\hat p_1 -\hat p_2 \pm z_{\alpha/2} SE

And for this case the confidence interval is given by:

0.11 \leq p_1 -p_2 \leq 0.39

Since the confidence interval not contains the value 0 we can conclude that we have significant difference between the two population proportion of interest 1% of significance given. So then we can't conclude that the two proportions are equal

4 0
3 years ago
On a normal distribution of iq test scores, the average score would be:
spayn [35]

The average IQ test score would be 100.

What is a normal distribution?

A probability distribution that is symmetric about the mean or average is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the average value occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.

Average IQ Score

A score of 100 is regarded as the average IQ on various tests. The majority of results (68%) are within one standard deviation of the mean (that is, between 85 and 115). This indicates that the average result is within plus or minus 15 points for almost 70% of test takers.

Learn more about average here:

brainly.com/question/2426692

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4 0
2 years ago
A piggy bank contains pennies, nickels, and dimes. The number of dimes is 15 more than the number of nickels, and there are 140
amm1812

Answer:

Option D is correct.

There are 34 nickels in the piggy bank.

Step-by-step explanation:

A piggy bank contains pennies, nickels and dimes.

Let the number of pennies be p

Let the number of nickels be n

Let the number of dimes be d

Also, note that 1 penny = $0.01

1 nickel = $0.05

1 dime = $0.10

- The number of dimes is 15 more than the number of nickels.

d = 15 + n

- There are 140 coins altogether totaling $7.17.

p + n + d = 140

0.01p + 0.05n + 0.1d = 7.17

Bringing the 3 equations together

d = 15 + n (eqn 1)

p + n + d = 140 (eqn 2)

0.01p + 0.05n + 0.1d = 7.17 (eqn 3)

Substitute (eqn 1) into (eqn 2)

p + n + d = 140

p + n + (15 + n) = 140

p + 2n + 15 = 140

p = 140 - 15 - 2n = 125 - 2n

p = 125 - 2n (eqn 4)

Substitute (eqn 1) and (eqn 4) into (eqn 3)

0.01p + 0.05n + 0.1d = 7.17

0.01(125 - 2n) + 0.05n + 0.1(15 + n) = 71.7

1.25 - 0.02n + 0.05n + 1.5 + 0.1n = 7.17

0.1n + 0.05n - 0.02n + 1.5 + 1.25 = 7.17

0.13n + 2.75 = 7.17

0.13n = 7.17 - 2.75 = 4.42

0.13n = 4.42

n = (4.42/0.13) = 34

d = 15 + n = 15 + 34 = 49

p = 125 -2n = 125 - (2×34) = 125 - 68 = 57

Hence, there are 57 pennies, 34 nickels and 49 dimes in the piggy bank.

Hope this Helps!!!

7 0
3 years ago
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