Answer:
<h2>For the first triangle, <u>x equals 22cm.</u></h2>
Here's how:-
x is the altitude or height of the triangle. To find it, we can use the Pythagoras theorem:-
The base is 120cm and the hypotenuse is 122cm
Putting this in the equation, we get:-
= 484
altitude = 
<h3>altitude = 22cm</h3><h2><u>So, x = 22cm</u></h2>
Answer:
this rule follow the airthmatics progression.
Answer:
L=21.6in and w=13.6
Step-by-step explanation:
If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8
Area is (width)(Length) = (width)(width+8)
W
----------
| |
| |
| | L = w+8
| |
| |
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A = (w+8)(w)
A = w2 + 8w = 295.
(Problem states that area is 295 sq in)
Need to solve this quadratic equation
w2 +8y - 295 = 0
Factor:
(w - 13.64) (w + 21.64) = 0
So
w - 13.64 = 0. or. w + 21.64= 0
Solve these and get
w = 13.64. or. w = -21.64
Only one that makes sense in real life is the poitive one.
So the dimensions are
Width = 13.64 inches
Length = 21.64 inches
X^5 (X to the fifth power) - 4 (x^5 - 4)
Answer:
3 is -3, 4 is 3
Step-by-step explanation:
In slope intercept form (y = mx+b)
m is the slope
b is the y-intercept
y = mx+b
y = -1(x) + 3
b = 3
