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Vlada [557]
3 years ago
12

g A coffee-dispensing machine is supposed to deliver eight ounces of liquid into each paper cup, but a consumer believes that th

e actual mean amount is less. The critical value for z for a one-tailed test with the tail in the left end is minus1.645 and the obtained value is minus1.87. The appropriate decision is ________.
Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer: Reject the eight- ounces claim.

Step-by-step explanation:

For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.

It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.

As per given ,

Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.

Then ,

H_0: \mu=8\\\\H_a: \mu , since alternative hypothesis is left-tailed thus the test is an left-tailed test.

the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.

Clearly , -1.87 < -1.645

⇒ -1.87 falls under rejection region.

⇒  Decision : Reject null hypothesis.

i.e. we reject the eight- ounces claim.

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Answer:

(2,-8)

Step-by-step explanation:

To reflect across the x axis make the y negative

8 is negative here

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3 years ago
URGENT HELP ME PLEASE
Trava [24]

Answer:

(a)\log_3(\dfrac{81}{3})=3

(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

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3 years ago
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Andrej [43]

Answer:

44°

Step-by-step explanation:

The sum of the angles in a triangle = 180°

In an isosceles triangle the base angles are equal, thus

base angle = \frac{180-92}{2} = \frac{88}{2} = 44°

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Step-by-step explanation:

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The answer would be 54 dollars
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