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umka21 [38]
3 years ago
6

If a university wants to maintain a 14:1 ratio between students and teachers, how many teachers would be needed to accommodate 8

96 students
Mathematics
2 answers:
zheka24 [161]3 years ago
7 0
<span>So we want to know the number of teachers the university should have if the ratio of students to teachers is 14:1 and the number of students is 896. If x is the number of teachers: 14/1=896/x. Now we solve for x: Lets multiply both sides with x: x*(14/1)=896 and divide both sides by 14 and we get: x=896/14 and x=64. So the university should have 64 teachers.</span>
atroni [7]3 years ago
5 0

Answer:64

Step-by-step explanation:

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Quadrilateral EFGH is on a coordinate plane. Segment FG is on the line 3x − y = −2, and segment EH is on the 3x − y = −6. Which
liberstina [14]

Answer:

the slope of both lines are the same.

Step-by-step explanation:

Given the following segment of the Quadrilateral EFGH on a coordinate  Segment FG is on the line 3x − y = −2,

segment EH is on the 3x − y = −6.

To determine their relationship, we can find the slope of the lines

For line FG: 3x - y = -2

Rewrite in standard form y = mx+c

-y = -3x - 2

Multiply through by-1

y = 3x + 2

Compare

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The slope of the line segment FG is 3

For line EH: 3x - y = -6

Rewrite in standard form y = mx+c

-y = -3x - 6

Multiply through by-1

y = 3x + 6

Compare

mx = 3x

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The slope of the line segment EH is 3

Hence the statement that proves their relationship is that the slope of both lines are the same.

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Answer:

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Step-by-step explanation:

set up equation based on WZ = W'Z'

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multiply each side of equation by 4 to eliminate fractions:

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substitute 5 for 'x' in either expression:

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Hoochie [10]

Answer:

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Second period: 3,2,3,1,3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

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The mean = ΣX / n

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Mean = 34 / 15 = 2.666

The median = 1/2(n+1)th term.

1/2(16)th term = 8th term.

The 8th term = 2

The best measure of centre is the mean because the values for the second period has no outliers that might have affected the centre of the distribution.

Both interquartile range and standard deviation are measures of spread and not measures of centre.

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