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umka21 [38]
3 years ago
6

If a university wants to maintain a 14:1 ratio between students and teachers, how many teachers would be needed to accommodate 8

96 students
Mathematics
2 answers:
zheka24 [161]3 years ago
7 0
<span>So we want to know the number of teachers the university should have if the ratio of students to teachers is 14:1 and the number of students is 896. If x is the number of teachers: 14/1=896/x. Now we solve for x: Lets multiply both sides with x: x*(14/1)=896 and divide both sides by 14 and we get: x=896/14 and x=64. So the university should have 64 teachers.</span>
atroni [7]3 years ago
5 0

Answer:64

Step-by-step explanation:

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I need help Write and expression equivalent to 1/4a-3​
Blizzard [7]

Answer:

Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.

Step-by-step explanation:

6 0
3 years ago
Raj fully simplified the polynomial and then put it in standard form with the last term being 6y3. 2x2y + 8x3 – xy2 – 2x3 + 3xy2
JulijaS [17]
Original polynomial:

2x^2 y + 8x^3 - xy^2 - 2x^3 + 3xy^2 + 6y^3


Order the polynomial in ascending order of y


8x^3 - 2x^3 + 2x^2y + 3xy^2 - xy^2 + 6y^3


Add up the similar terms:

6x^3 + 2x^2y + 2xy^2 + 6y^3 


Thats is the polynomial Raj ended up with.


And the first term  is 6x^3.


Answer: 6x^3
3 0
3 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
Select the correct answer. Which variable is likely to be linked to both of the variables mentioned in this statement?
aleksandrvk [35]

Answer:C

Step-by-step explanation:

Your answer seems to be C age of student.

Reason:

Here are the def for both variables:

Independent Variables: Are variables are testing:

Dependent Variables: Are variables that you are measuring.

Also reading score increases as you practice or get immunes to reading which could take years length of a person feet determines his growth spur.

Your answer is C.

Hope this Helps.

3 0
3 years ago
In how many ways can a teacher arrange 10 students in the front row if there are 60 total students
oksano4ka [1.4K]
The one in the first seat can be any one of 60.
               For each of those . . .
The one in the 2nd seat can be any one of the remaining 59.
               For each of those . . .
The one in the 3rd seat can be any one of the remaining 58.
               For each of those . . .
.
.
.
The one in the 9th seat can be any one of the remaining 52.
               For each of those . . .
The one in the 10th seat can be any one of the remaining 51.

Total number of ways to pick 10 students out of 60
and arrange them in 10 seats =

     (60·59·58·57·56·55·54·53·52·51)  =  273,589,847,200,000,000.
                                        (rounded to the nearest hundred million ways)

Number of ways to pick 10 students out of 60,
no matter how they sit =

           (60·59·58·57·56·55·54·53·52·51) / (10·9·8·7·6·5·4·3·2)

                =  75,394,027,560.  (rounded to the nearest 10 ways)

6 0
3 years ago
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