Answer:
Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.
Step-by-step explanation:
Original polynomial:
2x^2 y + 8x^3 - xy^2 - 2x^3 + 3xy^2 + 6y^3
Order the polynomial in ascending order of y
8x^3 - 2x^3 + 2x^2y + 3xy^2 - xy^2 + 6y^3
Add up the similar terms:
6x^3 + 2x^2y + 2xy^2 + 6y^3
Thats is the polynomial Raj ended up with.
And the first term is 6x^3.
Answer: 6x^3
Answer:

Step-by-step explanation:
The given differential equation is 
The characteristics equation is given by

Finding the values of r

We got a repeated roots. Hence, the solution of the differential equation is given by

On differentiating, we get

Apply the initial condition y (0)= 3 in equation (i)

Now, apply the initial condition y' (0)= 13 in equation (ii)

Therefore, the solution of the differential equation is

Answer:C
Step-by-step explanation:
Your answer seems to be C age of student.
Reason:
Here are the def for both variables:
Independent Variables: Are variables are testing:
Dependent Variables: Are variables that you are measuring.
Also reading score increases as you practice or get immunes to reading which could take years length of a person feet determines his growth spur.
Your answer is C.
Hope this Helps.
The one in the first seat can be any one of 60.
For each of those . . .
The one in the 2nd seat can be any one of the remaining 59.
For each of those . . .
The one in the 3rd seat can be any one of the remaining 58.
For each of those . . .
.
.
.
The one in the 9th seat can be any one of the remaining 52.
For each of those . . .
The one in the 10th seat can be any one of the remaining 51.
Total number of ways to pick 10 students out of 60
and arrange them in 10 seats =
(60·59·58·57·56·55·54·53·52·51) = 273,589,847,200,000,000.
(rounded to the nearest hundred million ways)
Number of ways to pick 10 students out of 60,
no matter how they sit =
(60·59·58·57·56·55·54·53·52·51) / (10·9·8·7·6·5·4·3·2)
= 75,394,027,560. (rounded to the nearest 10 ways)