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Ne4ueva [31]
3 years ago
5

The area of a rectangle painiting is given by the trinomial x^2-9x-36. what are the possible dimensions of the painting ? use fa

ctoring
Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0
<span> (x + 3) • (x - 12)
</span>

The first term is, <span> <span>x2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -9x </span> its coefficient is <span> -9 </span>.
The last term, "the constant", is <span> -36 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is  <span> -9 </span>.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -12  and  3 
                     <span>x2 - 12x</span> + 3x - 36

Step-4 : Add up the first 2 terms, pulling out like factors :
                    x • (x-12)
              Add up the last 2 terms, pulling out common factors :
                    3 • (x-12)
Step-5 : Add up the four terms of step 4 :
                    (x+3)  •  (x-12)
             Which is the desired factorization

Final result :<span> (x + 3) • (x - 12)</span>
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Answer:

Part 1) ∠ABD=23.9°

Part 2) ∠ADB=119.1°

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Step-by-step explanation:

Let

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see the attached figure with letters to better understand the problem

step 1

In the triangle ABD

Find the measure of angle ABD

Applying the law of sines

sin(37°)/349=sin(ABD)/235

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step 2

In the triangle ABD

Find the measure of angle ADB

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∠ADB+23.9°+37°=180°

∠ADB+23.9°+37°=180°-60.9°

∠ADB=119.1°

step 3

In the triangle ABD

Find the measure of side AB

Applying the law of sines

sin(37°)/349=sin(119.1°)/AB

AB=349*sin(119.1°)/sin(37°)

AB=506.7 ft

step 4

In the triangle BDE

Find the measure of angle BDE

we have

∠BDE+∠ADB=180° ----> by supplementary angles

∠ADB=119.1°

substitute

∠BDE+119.1°=180°

∠BDE=180°-119.1°

∠BDE=60.9°

step 5

In the triangle BDE

Find the measure of angle BED

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

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∠BED=77.1°

step 6

In the triangle BDE

Find the measure of side DE

Applying the law of sines

sin(77.1°)/349=sin(42°)/DE

DE=349*sin(42°)/sin(77.1°)

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step 7

In the triangle BDE

Find the measure of side BE

Applying the law of sines

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BE=349*sin(60.9°)/sin(77.1°)

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step 8

In the triangle BEC

Find the measure of angle BEC

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∠BEC+∠BED=180° ----> by supplementary angles

∠BED=77.1°

substitute

∠BEC+77.1°=180°

∠BEC=180°-77.1°

∠BEC=102.9°

step 9

In the triangle BEC

Find the measure of angle EBC

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

so

∠EBC+102.9°+41°=180°

∠EBC=180°-143.9°

∠EBC=36.1°

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