Answer: Found it by web and solving
Step-by-step explanation: L = W + 4
LW = 60
---
LW = 60
(W + 4)W = 60
W^2 + 4W + (-60) = 0
---
above is in quadratic equation form: ax^2 + bx + c = 0
---
use the quadratic formula to solve for two solutions:
x = ( -b +- sqrt( bb - 4ac ) ) / 2a
---
the two solutions are:
W = 6
W = -10
the negative solution doesn't make sense for length, so use the positive solution.
---
L = 10
W = 6
Answer:
Lower and Upper Class Limit
Step-by-step explanation:
The Lower class limit is the smallest value within the class and the Upper class limit is the largest value within the class.
In a grouped data, data are distributed into classes with a specific class size/interval. e.g. The Class 0-4 has a Class Size of 5. The Lower class limit in this case is 0 and the Upper Class Limit is 4.
It should be 5
Hope this helps
szaeAnswer:
fhx
Step-by-step explanation:ees
ffwsc
Answer:
< 5 gigabytes
Step-by-step explanation:
Let the number of gigabytes be represented as: g
Under her cell phone plan, Nicole pays a flat cost of $35 per month and $5 per gigabyte. She wants to keep her bill under $60 per month.
Under $60 = less than (<) $60
Hence, our inequality equation is given as:
$35 + $5 × g < 60
35 + 5g < 60
Collect like terms
5g < 60 - 35
5g < 25
g < 25/5
g < 5 gigabytes
Therefore, the number of gigabytes she can use while staying within her budget less than 5 gigabytes
