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3 years ago

NEED HELP QUCKILY PLZ HURRY

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

7 0

Hello from MrBillDoesMath!

Answer:

Discussion:

Parallel lines cut by a transversal has corresponding angles equal. . So the corresponding angles x and (3x-70) are equal. That is,

x = 3x - 70 => add 70 to both sides

x + 70 = 3x => subtract x from both sides

70 = 3x - x = 2x => divide both sides by 2

x = 70/2 = 35

which is the third choice

Thank you,

MrB

arlik [135]3 years ago

5 0

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4y-5x=-8

Dovator [93]

Answer:

4y−5x=−8

Step 1: Add -4y to both sides.

−5x+4y+−4y=−8+−4y

−5x=−4y−8

Step 2: Divide both sides by -5.

−5x

−5

−4y−8

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Step-by-step explanation:

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3 years ago

Represent this statement as an equation: The difference of twice a number and 3 is 11.

yan [13]

Answer:

2x - 3 = 11

Step-by-step explanation:

"difference" means subtraction, so it is subtraction.

"twice a number" simply means 2x, since you do not know what the specified number is, it is x. and the 2 and just making it twice the number.

"Is 11" just means equals 11.

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3 years ago

Does 23y+50+27y=50y+50 have one solution, no solution, or infinite solutions

stellarik [79]

The answer is infinite solutions.

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3 years ago

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A new bank customer with $3,500 wants to open a money market account. The bank is offering a simple interest of 1.6%.

Bond [772]

Answer:

A is $490 and B is 3990

Step-by-step explanation:

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3 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

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3 years ago

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