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3 years ago

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Heidi wants to buy a bike.She has already saved $57 and plans to save $12 per week.Consider the following information: y=12x+57

x= the number of weeks y= the total money saved .Which of the following statements is TRUE

1 answer:

djverab [1.8K]3 years ago

8 0

Answer:

It will increase by 12 every week, 57 is just what she already had, or in slope-intercept form, 57 is b

Step-by-step explanation:

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A teacher categorized students by whether they regularly completed their homework (or not) and whether they passed the course (o

ella [17]

Probabilities are used to determine the chances of an event.

Let P represents the event that a student passes the course, and C represents the event that a student completes the assignment

<u />

<u>(a) The probability a student passed the course given that they completed their homework?</u>

From the table, we have:

$\mathbf{n(P\ n\ C) = 25}$

$\mathbf{n(C) = 30}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C)}{n(C)}}$

This gives

$\mathbf{Pr = \frac{25}{30}}$

$\mathbf{Pr = 0.8333}$

Express as percentage

$\mathbf{Pr = 83.33\%}$

Hence, the probability a student passed the course given that they completed their homework is 83.33%

<u>(b) The probability a student passed the course given that they didn't complete their homework</u>

From the table, we have:

$\mathbf{n(P\ n\ C'= 7}$

$\mathbf{n(C') = 25}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C')}{n(C')}}$

This gives

$\mathbf{Pr = \frac{7}{25}}$

$\mathbf{Pr = 0.28}$

Express as percentage

$\mathbf{Pr = 28\%}$

Hence, the probability a student passed the course given that they didn't complete their homework is 28%

<u>(c) The probability a student completed their homework given that passed the course?</u>

From the table, we have:

$\mathbf{n(P\ n\ C) = 25}$

$\mathbf{n(P) = 32}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C)}{n(P)}}$

This gives

$\mathbf{Pr = \frac{25}{32}}$

$\mathbf{Pr = 0.78125}$

Express as percentage

$\mathbf{Pr = 78.125\%}$

Approximate

$\mathbf{Pr = 78.13\%}$

Hence, the probability a student completed their homework given that they passed the course is 78.13%

<u>(d) The probability a student didn't complete their homework given that they didn't pass the course </u>

From the table, we have:

$\mathbf{n(P'\ n\ C'= 18}$

$\mathbf{n(P) = 23}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P'\ n\ C')}{n(P')}}$

This gives

$\mathbf{Pr = \frac{18}{23}}$

$\mathbf{Pr = 0.7826}$

Express as percentage

$\mathbf{Pr = 78.26\%}$

Hence, the probability a student didn't complete their homework given that they didn't pass the course is 78.26%

Read more about probabilities at:

brainly.com/question/11234923

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3 years ago

Help with this please!

belka [17]

Answer:

47

Step-by-step explanation:

mean is found by dividing the sum of the terms by the number of terms:

(43+48+41+41+x)/5=44

173+x=220

x=220-172=47

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3 years ago

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