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3 years ago

Which criterion can be used to prove ABC and ADC are congruent?

Mathematics

2 answers:

Darya [45]3 years ago

6 0

Answer:

D. ASA

Step-by-step explanation:

In triangles ABC and ADC,

Angles BCA and DAC are congruent (from the diagram);
Angles BAC and DCA are congruent (from the diagram);
AC is congruent AC (by reflexive property).

So, the triangles ABC and CDA are congruent by ASA postulate.

ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

faltersainse [42]3 years ago

6 0

Answer:

c. ASA

Step-by-step explanation:

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goldfiish [28.3K]

Answer:

Step-by-step explanation:

let they meet after t hours

2.5t+3t=22

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55/10 t=22

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3 years ago

Read 2 more answers

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

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3 years ago

Write in numeral form 4*100+2*10+8(6*1/10) +(1*1/100)

Mice21 [21]

Answer:428 7/100

Step-by-step explanation:

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2 years ago

Jenny and Mark are reading the same book for their English class.

Harrizon [31]

Answer:

10 days

Step-by-step explanation:

Jenny has read 50 pages and will read 15 each day.

The equation would be: 15x+50

Mark will read 20 pages daily.

The equation would be: 20x

In both equations x represents days.

You set both equal to each other because you want to know when they read the same amount of pages.

15x+50=20x

...you subtract 15x from both sides

50=5x

...and divide by five to get: 10 days

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