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Maru [420]
2 years ago
11

Solve the proportion for x. 2/9=3/(x+2)

Mathematics
2 answers:
attashe74 [19]2 years ago
7 0

Answer:

x as a fraction: 11\frac{1}{2}

Step-by-step explanation:

Variable x cannot be equal to −2 since division by zero is not defined. Multiply both sides of the equation by 9(x+2), the least common multiple of 9,x+2.

2 ( x+ 2) = 9 x 3

Use the distributive property to multiply 2 by x + 2.

2x + 4 = 9 x 3

Multiply 9 and 3 to get 27.

2x + 4 = 27

Subtract 4 from both sides.

2x = 27 - 4

Subtract 4 from 27 to get 23.

2x = 23

Divide both sides by 2.

x = \frac{23}{2}

Simplify

11\frac{1}{2}

Hope it helps and have a great day! =D

~sunshine~

barxatty [35]2 years ago
4 0

Answer:

x=\frac{23}{2}

Step-by-step explanation:

Hi there!
We are given the following proportion:

\frac{2}{9} =\frac{3}{x+2}, and we want to solve it for x

To solve proportions, we can cross-multiply; in other words, we can multiply the terms in the numerator of one proportion with the terms in the denominator of the second proportion.

This is a property that where if you have the proportion \frac{a}{b} =\frac{c}{d}, it can also be represented as ad=bc
So let's cross multiply; multiply 2 by x+2, and multiply 9 by 3. Then, set them equal to each other.

2(x+2)=9*3

Multiply

2x+4=27
Subtract 4 from both sides

2x=23

Divide both sides by 2

x=\frac{23}{2}
The answer can be left as that.
Hope this helps!

If you wish to solve a similar problem for practice, take a look here: brainly.com/question/24355081

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Step-by-step explanation:

Step 1: Subtract 6 from both sides.

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A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat
sladkih [1.3K]
<h2>Question: </h2>

A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat at a gain of 10% and the spoiled when at a loss of 25%. Find his total gain or loss per cent.

Answer:

<h2>5%</h2>

<h2>step by step answer:</h2>

In the question we are given a shopkeeper or bought wheat for Rs. 35000. Now, due to leakage 17 of the total wheat is spoiled. Now, he sold the good wheat at 10% gain and the bad wheat at 25% loss. We need to find the total gain/loss percent.

According to the problem, the total cost of wheat is Rs. 35000.

Now, let us find the cost price of the spoiled wheat.

So, the cost of spoiled wheat is 17×Rs35000 which is equal to Rs. 5000.

Hence, the cost price of spoiled wheat is Rs 5000.

As we know that the spoiled wheat was sold at 25% loss, so we can say that if the cost price is considered as 100% so the selling price is considered as (100−25)% or 75%.

So, we got the selling price of spoiled wheat is 75100×5000=Rs3750

So, the cost price of spoiled wheat is Rs.5000 and selling price of spoiled wheat is Rs.3750.

Now, let us find the cost price of the good wheat.

Now, we will consider the good quality of wheat whose cost price is Rs(35000−5000) which is Rs. 30000.

Hence, the cost price is Rs. 30000.

As we know good quality wheat was sold at 10% gain so we can say that, if the cost price is 100% then the selling price will be (100+10)% or 110% .

Hence, the selling price of good quality wheat is 110100×Rs30000 which is Rs. 33000.

So, the cost price of good quality wheat is Rs. 30000 and selling price is Rs. 33000.

Let us find the total selling price of the wheat that the shopkeeper bought.

Now the total selling price of the wheat is Rs.3750+Rs.30000=Rs.36750.

Hence Profit = Total selling price − Total cost price

profit =Rs.36750−Rs.35000

=Rs.1750

profit %

=profitcost price×100%.

=175035000×100%.

=5%.

<h2>So, total profit is 5%.</h2>
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