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natita [175]
3 years ago
13

Which situation would be considered pseudoscience?

Chemistry
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

The correct answer is the option 4: A student's lucky shirt helps him do well on a job interview

Explanation:

Pseudoscience is the name given to the practises, statements or beliefs that a person established for himself without any base on the science world. That means that this beliefs are incompatible with the scientific method and therefore that are not an absolute truth in what they state.

Therefore that the situation where a student believes that his lucky shirt helps him to do well in the a job interview are totally subjective and not absolutely true.

Tcecarenko [31]3 years ago
5 0
A student tries eating all natural foods for one month to see if she has more energy
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Answer:

guidelines

Explanation:

It gives perameters for her abilities :)

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3 years ago
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A sample of water is mixed with a surfactant.what will most likely happen to the viscosity of the water?
GenaCL600 [577]
The viscosity will decrease
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What is the reason for the trend in Electron Affinity? Select all that apply.
Jlenok [28]

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"How many formula units are there in sample of copper(II) sulfate that has
babymother [125]

Answer: 1.23\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{32.5g}{160g/mol}=0.203moles

1 mole of CuSO_4 contains 6.023\times 10^{23} of formula units

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8 0
4 years ago
How many grams of fosforic acid (H3PO4) are required to prepare 500 mL of a 0.2 M solution?
navik [9.2K]

Answer:

Mass = 9.8 g

Explanation:

Given data:

Molarity of solution = 0.2 M

Volume of solution = 500 mL

Number of grams of phosphoric acid = ?

Solution:

First of all we will convert the volume milliliter to litter.

500 mL × 1 L/1000 mL

0.5 L

Molarity = moles of solute / volume in litter

0.2 M =  number of moles / volume in litter

Number of moles = 0.2 mol/L × 0.5 L

Number of moles = 0.1 mol

Number of grams:

Number of moles = mass/molar mass

Mass = number of moles × molar mass

Mass = 0.1 mol × 98 g/mol

Mass = 9.8 g

7 0
3 years ago
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