Question

-336x2y3 Reduce to lowest terms

Answer 1

Answer:

$-\frac{42y}{x}$

Step-by-step explanation:

Apply the fraction rule: $\frac{-a}{b}=-\frac{a}{b}$

$=-\frac{336x^2y^3}{8x^3y^2}$

Divide the numbers: $\frac{336}{8} =42$

$=\frac{42x^2y^3}{x^3y^2}$

Apply the exponent rule: $\frac{x^a}{x^b}=\frac{1}{x^{b-a}}$

$\frac{x^2}{x^3}=\frac{1}{x^{3-2}}$

$=\frac{42y^3}{y^2x^{3-2}}$

Subtract the numbers: $\:3-2=1$

$=\frac{42y^3}{xy^2}$

Apply the exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$\frac{y^3}{y^2}=y^{3-2}$

$=\frac{42y^{3-2}}{x}$

Subtract the numbers: $3-2=1$

$=-\frac{42y}{x}$