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2 years ago

What is the distance between the florist’s shop (D) and the car wash (E)? Explain using coordinate subtraction.

Mathematics

1 answer:

VARVARA [1.3K]2 years ago

5 0

Answer:

hi! once you link the picture I will answer the problem.

Step-by-step explanation:

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Find the absolute maximum and minimum values of f(x.y)=x^2+y^2-2x-2y on the closed region bounded by the triangle with vertices

dem82 [27]

Try this suggested solution, note, 'D' means the region bounded by the triangle according to the condition. It consists of 6 steps.

Answers are underlined with red colour.

6 0

3 years ago

PLEASE HELP ME I WILL MARK TOU JT YOU HELP ME!!!

Elden [556K]

Given:

The figure of a construction.

To find:

The correct option that represents the given construction.

Solution:

In the given figure, the given angle is angle CAB.

The steps for the given figure are:

1. Draw a ray PQ.

2. Mark an arc BC on the given angle and mark the same arc on the line and the intersection of line and arc is point Q.

3. Set the compass of the length BA.

4. Put the compass on the point Q mark arc that intersect the first arc. The intersection of arcs is R.

5. Draw a ray PR.

These are the steps of construction to copy an angle.

Therefore, the correct option is A.

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3 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

2 years ago

Identify the matrix transformation of ΔKLM, which has coordinates K(−2, 3),L(−4, −2), and M(−3, 0), for reflection across the x-

mafiozo [28]

Lol Kinda hard try again

3 0

2 years ago

Quinn had $4.00. He spent 1/2 of his money on a baseball card, 1/4 of it on a drink, and 1/8 of it on bubble gum. How much mone

Pepsi [2]

Answer:

$0.50

Step-by-step explanation:

He spent 2 on a card 1 on a drink and 1/2 on a piece of gum.

4 - (2+1+1/2) = 1/2

I am not sure it's correct.

4 0

2 years ago

Read 2 more answers