D. Polarity and size.
<span>The size, polarity, and charge of a substance will determine whether or not the substance can cross the cell membrane by diffusion. The cholesterol was an example of a lipid, and is highly soluble in the nonpolar environment of the lipid bilayer. You saw, in the animation above, the cholesterol freely passing into the hydrophobic environment of the membrane. Cholesterol distributes freely in the membrane and then some fraction will dissolve in the aqueous environment of the cytoplasm. Water, on the other hand, while polar, is small enough to cross the membrane at a slow rate. Note that specialized transport proteins in certain cell membranes can provide a channel for the water, greatly increasing its rate of crossing the membrane. The lipid bilayer is much less permeable to the ion, because of its charge and larger size. As a general rule, charged molecules are much less permeable to the lipid bilayer.</span>
B. i guess ! don’t mind this brainly told me to put 20 characters.
Answer:
The most appropriate answer would be The cell will not make functional proteins from that mRNA strand.
The amino acid sequence of the proteins is derived from the nucleotide sequence of the mRNA (messenger ribonucleotide).
If the sequence of mRNA is miscopied, it will change the sequence of amino acids of the protein.
Consequently, the protein may become non-functional.
Answer:
The answer is XX.
Explanation:
Let us say that X is the dominant gene and x is the recessive gene for the height of the pea plants. Pea plants need to be homozygous or heterozygous to have the short phenotype which means it needs to have the genotype xx or Xx.
The F2 offspring has a ratio of 74,5% tall plants and 25,5% short plants. For these results, the stem height pea plant needs to be homozygous which is an XX genotype for the tall pea plant.
I hope this answer helps.
