2.67 +4.56 hjkfghjfvgbn

Mathematics

2 answers:

riadik2000 [5.3K]2 years ago

8 0

Answer:

7.23

Step-by-step explanation:

vfiekz [6]2 years ago

5 0

Answer:

7.23

Step-by-step explanation:

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jewels score was 5 over par on the first 1 holes. her score was 4 under on the second 9 holes. what is this but in integers

melamori03 [73]

Answer:

Step-by-step explanation:

In golf, if you are over par, then your score is represented by values over zero and with a plus. Since Jewels' score was 5 over on the first hole (dang... that's a quintuple bogey (which is horrible)), she had a +5 on the first hole. But for the next 9 holes, she scored 4 under, which is represented by -4. Add 5 and -4 and you get +1. She still has 8 holes left in that round if she wants to get below par.

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A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. What is the probability of choosing a green marble, not replacing it

lys-0071 [83]

The probability for choosing green and red is $\frac{1}{12}$

Solution:

Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.

We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?

Now, we know that,

$\text { probability of an event }=\frac{\text { number of favourable outcomes }}{\text { total number of outcomes }}$

So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4

$\text { Now, probability for green marble }=\frac{1 \text { green marble }}{4 \text { marbles }}=\frac{1}{4}$

And now, total outcomes will be only 3 as we are not replacing the picked marble.

$\begin{array}{l}{\text { Then, probability for red marble }=\frac{1 \text { red marble }}{3 \text { marbles }}=\frac{1}{3}} \\\\ {\text { Then overall probability }=\frac{1}{4} \times \frac{1}{3}=\frac{1}{12}}\end{array}$