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GrogVix [38]
4 years ago
6

Hank and Debra each one two milking cows. One day, they Milked their cows and compared the amount of milk the cows produced in t

hat day
Mathematics
1 answer:
Alexandra [31]4 years ago
3 0
It would be great if you provided a question here..!
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Solve for m.<br> m + 7 &gt; 5
anastassius [24]

Answer:Move all terms not containing  

m

to the right side of the equation.

Tap for more steps...

m

7

=

14

Multiply both sides of the equation by  

7

.

7

⋅

m

7

=

7

⋅

14

Simplify both sides of the equation.

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m

=

98

Step-by-step explanation:

pls give me  BRAINLIESTT PLSSSSSSS

5 0
3 years ago
Tanesha is saving up to buy a video game system that costs $350. The graph shows her savings.
Jobisdone [24]

Answer:c

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
What does b equal. 2/3b +19=35
tia_tia [17]

2/3b + 19 = 35

          -19    -19

----------------------

2/3b  =  16

÷2/3    ÷2/3

----------------------

b  =  24

7 0
3 years ago
A sample of 25 commuters in the Washington, D.C., area yielded the sample mean commute time of 27.97 minutes and sample standard
xxMikexx [17]

Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes. The interpretation is that we are 99% sure that the true mean ommute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{10.04}{\sqrt{25}} = 5.1706

The lower end of the interval is the mean subtracted by M. So it is 27.97 - 5.1706 = 22.7994 minutes

The upper end of the interval is the mean added to M. So it is 6.4 + 0.3944 = 33.1406 minutes.

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes. The interpretation is that we are 99% sure that the true mean ommute time of all commuters in Washington D.C. area is between 22.7994 minutes and 33.1406 minutes.

5 0
4 years ago
Using Colored Counters, where yellow counters are positive and red counters are negative, model 5 (use 7 chips)
vova2212 [387]

Answer:

Step-by-step explanation:

??

8 0
2 years ago
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