Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
The equation that can be used to represent total tickets sales is 2170 = 5s + 2f + 10a
<h3>Equation</h3>
let
- Number of students tickets = s
- Number of faculty tickets = f
- Number of alumni tickets = a
Expression for number of students tickets sold;
s = f + 15
Expression for number of faculty tickets sold;
f = 2a
Expression for number of alumni tickets sold;
f = 2a
a = f/2
- Cost of students tickets = $5
- Cost of faculty tickets = $2
- Cost of Alumni tickets= $10
- Total revenue = $2170
2170 = 5s + 2f + 10a
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Answer:
true
Step-by-step explanation:
because it would be
Answer:
9(6+3) = 54+27
Step-by-step explanation:
dunno how to explain but hope the answer helps
In mathematics, number with a symbol of a point, is expressed in decimal form. When they are read, the numbers after the decimal point are read digit after digit. Therefore, in word form, the number is read as: Two hundred nine point one zero six.