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Virty [35]
3 years ago
7

A manufacturing unit currently operates at 80 percent of its capacity. The profit function for the unit at the optimum output, x

, is given by p(x) = -0.1x^2 + 80x − 60.
If the function f(x) models the current capacity of the unit, the composite function giving the unit's current profit function is a.f(p(x))=-0.064x^2+6.4x-60
b.p(f(x))=-0.64x^2+0.64x-60
c.p(f(x))=-0.064x^2+64x-60
d.p(f(x))=-0.64x^2+6.4x-60
e.f(p(x))=-0.064x^2+64x-60
If the optimum output is 500 units, the current profit is $a.15,400 b.15,940 c.16,060 d.16,600
Mathematics
1 answer:
dem82 [27]3 years ago
5 0

Answer:

The correct answers are c. p(f(x)) = -.064x^2+64x-60

and b. 15,940.

Step-by-step explanation:

This is correct on the test

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In the following exercises, solve
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Answer:

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Step-by-step explanation:

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  • Calculate the volume to the nearest whole number.
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Step 1 of 2

Write the inversely proportionality relation between the volume and pressure of a gas in container.

$v \propto \frac{1}{p}$

Where volume is represented by v and pressure is represented by p.

Remove the proportionality and place a constant say k.

$v=\frac{k}{p}$

Substitute the given values of nitrogen that v=29.5 and

p=2000 and calculate the value of k from above equation.

$$\begin{aligned}&29.5=\frac{k}{2000} \\&\Rightarrow k=29.5 \times 2000 \\&\Rightarrow k=59000\end{aligned}$$

Step 2 of 2

Substitute the value p=14.7 and above calculated k value in the equation

$$\begin{aligned}&v=\frac{k}{p} . \\&v=\frac{59000}{14.7} \\&\Rightarrow v=4013.6\end{aligned}$$

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