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2 years ago

????? pls help hdjsjddh

Mathematics

1 answer:

ASHA 777 [7]2 years ago

5 0

Multiplying by 2 and dividing by 3 since in that expression to simplify it you could just put 18 on the numerator multiplying by two

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Which answer has the smallest value?

Mademuasel [1]

Answer:

The smallest value is 2) the opposite of 50 because it is farthest left of the zero (this makes it the smallest)

Step-by-step explanation:

1) = 100

2) = -50

3) = 0

4) = -25

5) = -5

6 0

3 years ago

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Which of the following is not a polygon

sp2606 [1]

PLEASE PROVIDE AN EXAMPLE!

Without an example, the only thing I can tell you is a Polygon is a plane figure with three straight sides (or more) and angles. (usually 5 or more.)

-

Sorry, This was all I could provide with the amount of information given, please try to provide more information! If you have extra information, please let me know and I'll be sure to help!

7 0

3 years ago

LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

klasskru [66]

$\huge \bf༆ Answer ༄$

Let's solve ~

$\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }$

$\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times 3{k}^{4} }$

$\qquad \looparrowright \sf - 2 \times 2 {}^{3} \times {k}^{2} \times \sqrt{3}$

$\qquad \looparrowright \sf - 16 {k}^{2} \sqrt{3}$

Hence, the correct choice is D

5 0

2 years ago

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Alyssa spent 9.20 for 16 packs of gum at this rate how much would it cost alyssa to buy 30 packs of gum.

zhuklara [117]

$17.25. Divide 9.20 by 16 and mulitply by 30.

6 0

3 years ago

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

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????? pls help hdjsjddh​

????? pls help hdjsjddh