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dmitriy555 [2]
4 years ago
11

Approximately how long has the Moon been geologically inactive?

Chemistry
2 answers:
nikdorinn [45]4 years ago
6 0
About one billion years, so A
Stels [109]4 years ago
3 0
The answer is A. 1 billion years hope this help :)


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Earth's oceans have an average depth of 3800 m, a total surface area of 3.63 x 108 km2, and an average concentration of dissolve
kakasveta [241]

Answer:

a) Mass of gold in ocean = 8.1*10¹² g

b) Volume of gold = 4.2*10¹¹ cm³

c) Value of gold = $ 4.1*10¹³

Explanation:

a) Depth of ocean = 3800 m

Surface area of ocean = 3.63*10⁸ km²

Now, 10⁶ m² = 1 km²

Therefore, the area in units of m² = 3.63*10¹⁴ m²

Volume\ of\ ocean = Depth*Area = 3800m*3.63*10^{14} m2=1.4*10^{18} m3

Average concentration of gold in ocean = 5.8*10⁻⁹ g/L

Now, 1 g/L = 1000 g/m³

Therefore, concentration of gold in g/m³ = 5.8*10⁻⁶ g/m³

Mass\ of\ gold =1.4*10^{18} m^{3} *5.8*10^{-6} g/m3 = 8.1*10^{12} g

b) Mass of gold present = 8.1*10¹² g

Density of gold = 19.3 g/cm³

Volume\ of\ gold = \frac{Mass}{density} =\frac{8.1*10^{12} }{19.3} =4.2*10^{11} cm^{3}

c) Price of gold = $1595/troy oz

Unit conversion

1 troy oz = 311 g

Therefore, 8.1*10¹² g of gold is equivalent to:

\frac{8.1*10^{12} g* 1\  troy\ oz}{311g} =2.6*10^{10} \ troy\ oz

The value of gold in the ocean is:

\frac{2.6*10^{10} troy\ oz*1595\ dollars}{1\ troy\  oz} =4.1*10^{13} \ dollars

5 0
4 years ago
What do you think you’d be able to tell about an organism from its fossilized parts?
Andre45 [30]

you would probably be able to see the organism's age and/or how long its bones have been fossilized.

3 0
3 years ago
Read 2 more answers
1. How many grams are there in 7.5 x 1023 molecules of H2SO4?
Karo-lina-s [1.5K]

Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×10^{23} molecules of H_{2} SO_{4}?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02×10^{23}

∴\frac{7.5*10^{23} }{6.02*10^{23}}=1.25 mol(2d.p.)

Lastly, find the grams using the formula M= \frac{m}{n}

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

M= \frac{m}{n} (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \frac {molecular mass} {6.02*10^{23}} = moles

5 0
3 years ago
Did I do everything right?
nikitadnepr [17]
WHAT DO YOU MEAN?????
5 0
3 years ago
How many unpaired electrons does lithium have.
Marianna [84]

Answer:

Lithium only has one pair of unpaired electrons.

Explanation:

7 0
3 years ago
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