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dmitriy555 [2]
3 years ago
11

Approximately how long has the Moon been geologically inactive?

Chemistry
2 answers:
nikdorinn [45]3 years ago
6 0
About one billion years, so A
Stels [109]3 years ago
3 0
The answer is A. 1 billion years hope this help :)


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1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.
Alexxx [7]

Answer:

n=1.732mol

\% N=18.7\%

Explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

Best regards!

4 0
3 years ago
Experiments are often performed in science to produce data or evidence. This evidence is then analyzed to draw conclusions. The
Deffense [45]

Answer: Scientific Methods

Explanation:

Scientific Methods means arriving at a valid conclusion based on overwhelming scientific evidences obtained through experiments. Science is empirical in its approach to seeking knowledge. Science encourages empiricism by its heavy reliance on experimental results in the construction of its arguments and arriving at its conclusions.

4 0
3 years ago
Read 2 more answers
Which of the following has zero acceleration?
belka [17]
'Acceleration' means any change in speed or direction
of motion.

so
 C).  No acceleration.  Straight, at constant speed. 
No change of speed or direction.
5 0
3 years ago
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When the following equation is balanced, what is the coefficient of oxygen?
Gwar [14]

Answer:

The answer is 3

C2H5OH + O2 CO2 +H2O (unbalanced)

C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)

4 0
3 years ago
Acetic acid has a Kb of 2.93 °C/m and a normal boiling point of 118.1 °C. What would be the boiling point of a solution made by
alexdok [17]

Boiling point elevation is given as:

ΔTb=iKbm

Where,

ΔTb=elevation in the boiling point

that is given by expression:

ΔTb=Tb (solution) - Tb (pure solvent)

Here Tb (pure solvent)=118.1 °C

i for CaCO3= 2

Kb=2.93 °C/m

m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)

=(100.0÷100 g/mol)/0.4

= 2.5 m

So now putting value of m, i and Kb in the boiling point elevation equation we get:

ΔTb=iKbm

=2×2.93×2.5

=14.65 °C

boiling point of a solution can be calculated:

ΔTb=Tb (solution) - Tb (pure solvent)

14.65=Tb (solution)-118.1

Tb (solution)=118.1+14.65

=132.75

3 0
3 years ago
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