Answer:
a) Mass of gold in ocean = 8.1*10¹² g
b) Volume of gold = 4.2*10¹¹ cm³
c) Value of gold = $ 4.1*10¹³
Explanation:
a) Depth of ocean = 3800 m
Surface area of ocean = 3.63*10⁸ km²
Now, 10⁶ m² = 1 km²
Therefore, the area in units of m² = 3.63*10¹⁴ m²

Average concentration of gold in ocean = 5.8*10⁻⁹ g/L
Now, 1 g/L = 1000 g/m³
Therefore, concentration of gold in g/m³ = 5.8*10⁻⁶ g/m³

b) Mass of gold present = 8.1*10¹² g
Density of gold = 19.3 g/cm³

c) Price of gold = $1595/troy oz
Unit conversion
1 troy oz = 311 g
Therefore, 8.1*10¹² g of gold is equivalent to:

The value of gold in the ocean is:

you would probably be able to see the organism's age and/or how long its bones have been fossilized.
Answer:
I cannot give you all the answer but I can help you to solve those.
Explanation:
The first question:
How many grams are there in 7.5×
molecules of
?
So we need to find the molecular mass first, use your periodic table,
And then we can find out 2+32+16×4=98 g/mol
Then, we need to find how many moles, by using Avogadro's constant:
Avogadro's constant: 1 mole = 6.02×
∴
=1.25 mol(2d.p.)
Lastly, find the grams using the formula 
m=Mn
m=1.25*98
m=122.5g
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In conclusion, use those formula to help you:
(which M = molecular mass(atomic mass) m=mass of the substance and n = moles)
Avogadro's constant: 
Answer:
Lithium only has one pair of unpaired electrons.
Explanation: