171 because 57x3=171.
BOOM!!
Shakalaka.
Answer:
90.3 g
Explanation:
Calculate the <em>mass of the liquid</em>
D = M/V Multiply both sides by V and transpose
M = V × D
V = 20.5 mL
D = 0.9856 g/mL Calculate M
M =20.5 × 0.9856
M = 20.20 g
===============
Calculate the <em>mass of the cylinder</em>
Mass of cylinder = mass of (cylinder + liquid) – mass of cylinder
Mass of cylinder + liquid = 110.4567 g Calculate mass of cylinder
Mass of cylinder = 110.4567 – 20.20
Mass of cylinder = 90.3 g
Notice that the oxygen atom produced in the first step of this mechanism is consumed in the second step and therefore does not appear as a product in the overall reaction. Species that are produced in one step and consumed in a subsequent step are called intermediates.
I hope that helps
ps. not my words, my older cousins
Answer:
Since 2H₂ + O₂ ---> 2H₂O
We need 2 moles of hydrogen for each mole of oxygen
So, we need 2(6) = 12 moles of H₂ but since we only have 10 moles,
H₂ is the limiting reagent
So since 2 moles of H₂ gives 2 moles of water,
10 moles of H₂ will give rise to 10 moles of Water with 1 mole of remaining oxygen