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s344n2d4d5 [400]
3 years ago
13

Names of the sugar acid produced by the oxidation of d-ribose

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
5 0

Oxidation of D -Ribose in presence of hypobromous acid gives D-Ribonic acid

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What happens when sugar is heated? Give a balanced equation
mario62 [17]

Answer:

when the sugar is heated it turn out in caramelize

8 0
2 years ago
when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc
OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0
3 years ago
Chất nào sau đây là chất điện li mạnh trong H2O
erica [24]

Answer:

những lựa chọn ở đâu?

Explanation:

Hy vọng nó sẽ giúp ích;>

3 0
3 years ago
Read 2 more answers
Which planets mass is nearly double that of mercury?
Nana76 [90]

Answer:

earth I think like that because earth is the second planet

4 0
2 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
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