Answer:

Explanation:
When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.
First, we must set up Avogadro's number as a ratio.

Next, multiply the number of moles by the ratio.

When we multiply, the moles of silicon will cancel.

Since the denominator of the fraction is 1, we can cancel it out too.


The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.
The 0 in the hundredth place tells us to leave the 5 in the tenth place.

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>
Cytosine (C) and Guanine (G) are more steady under expanding heat since C and G have three hydrogen bonds while Adenine (An) and Thymine (T) have just two. The more hydrogen bonds there are, the more steady the nucleotides are. More bond dependability requires more warmth vitality to separate the securities, and since G≡C have more hydrogen securities than A=T, they are thusly more steady under expanding heat.
Answer:
cellular respiration is a critical function by which cells release energy for various cellular activities like locomotion, biosynthesis, and even the transportation of molecules between membranes.
Answer:

Explanation:
Hello,
In this case, considering the given reaction:

Thus, for the equilibrium, just water and hydrogen participate as iron and iron(II,III) oxide are solid:
![Kc=\frac{[H_2]^4}{[H_2O]^4}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2%5D%5E4%7D%7B%5BH_2O%5D%5E4%7D)
Thus, at the beginning, the concentration of water is 0.05 M and consequently, at equilibrium, considering the ICE procedure, we have:

Thus, the change
is obtained as:
![\sqrt[4]{5.1} =\sqrt[4]{[\frac{(4x)}{(0.05M-4x)}]^4}\\\\1.5=\frac{(4x)}{(0.05M-4x)}\\\\x=0.0075M](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5.1%7D%20%3D%5Csqrt%5B4%5D%7B%5B%5Cfrac%7B%284x%29%7D%7B%280.05M-4x%29%7D%5D%5E4%7D%5C%5C%5C%5C1.5%3D%5Cfrac%7B%284x%29%7D%7B%280.05M-4x%29%7D%5C%5C%5C%5Cx%3D0.0075M)
Thus, the moles of hydrogen at equilibrium are:
![[H_2]_{eq}=4*0.0075\frac{mol}{L}*1.0L=0.03molH_2](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D4%2A0.0075%5Cfrac%7Bmol%7D%7BL%7D%2A1.0L%3D0.03molH_2)
Therefore, the grams of iron(II,III) oxide finally result:

Best regards.