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stepladder [879]
3 years ago
9

1. How many grams are there in 7.5 x 1023 molecules of H2SO4?

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×10^{23} molecules of H_{2} SO_{4}?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02×10^{23}

∴\frac{7.5*10^{23} }{6.02*10^{23}}=1.25 mol(2d.p.)

Lastly, find the grams using the formula M= \frac{m}{n}

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

M= \frac{m}{n} (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \frac {molecular mass} {6.02*10^{23}} = moles

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Answer:

\boxed {\boxed {\sf About \ 1.5 * 10^{24} \ atoms \ Si}}

Explanation:

When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.

First, we must set up Avogadro's number as a ratio.

\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

Next, multiply the number of moles by the ratio.

2.5 \ mol \ Si *\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

When we multiply, the moles of silicon will cancel.

2.5 * \frac {6.022 \ * 10^{23} \ atoms \ Si }{1}}

Since the denominator of the fraction is 1, we can cancel it out too.

2.5 *  {6.022 \ * 10^{23} \ atoms \ Si }

1.5055 * 10^{24} \ atoms \ Si

The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.

The 0 in the hundredth place tells us to leave the 5 in the tenth place.

1.5 * 10^{24} \ atoms \ Si

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>

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Given what you have learned about the hydrogen bonding shared between nucleic acids in dna, which pair is more stable under incr
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3 years ago
Consider the following reaction. 3 Fe(s) + 4 H2O(g) Fe3O4(s) + 4 H2(g) At 900°C, Kc for the reaction is 5.1. If 0.050 mol of H2O
Oduvanchick [21]

Answer:

m_{Fe_3O_4}=1.7gFe_3O_4

Explanation:

Hello,

In this case, considering the given reaction:

3 Fe(s) + 4 H_2O(g) \rightleftharpoons Fe_3O_4(s) + 4 H_2(g)

Thus, for the equilibrium, just water and hydrogen participate as iron and iron(II,III) oxide are solid:

Kc=\frac{[H_2]^4}{[H_2O]^4}

Thus, at the beginning, the concentration of water is 0.05 M and consequently, at equilibrium, considering the ICE procedure, we have:

5.1=\frac{(4x)^4}{(0.05M-4x)^4}

Thus, the change x is obtained as:

\sqrt[4]{5.1} =\sqrt[4]{[\frac{(4x)}{(0.05M-4x)}]^4}\\\\1.5=\frac{(4x)}{(0.05M-4x)}\\\\x=0.0075M

Thus, the moles of hydrogen at equilibrium are:

[H_2]_{eq}=4*0.0075\frac{mol}{L}*1.0L=0.03molH_2

Therefore, the grams of iron(II,III) oxide finally result:

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Best regards.

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