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4 years ago

Please click on the photo and answer ASAP!!!! Worth 90points!!!! Please also try to include working out!!!!

Mathematics

2 answers:

Oksanka [162]4 years ago

8 0

Answers: ( '/' means divides by)

Q4 is 720miles

mph = 240

3hrs = 240 x 3

Q5 is 31.5mph

2 hrs = 65miles

1mile = 65/2

Q6 is 4 hours

20miles in 1hour

80 miles = 80/20

Q7 is 3cm

30secs = 0.5cm

60sec(1min) = 60 x 0.5

Q8 is 15km per hour

5hrs = 75km

1hr = 75/5

Q9 is 7hrs 30mins

20miles per hour meaning 1 hour

150miles = 150/20

Q10 is 165miles

distance between 4pm and 7pm is 3 hours

55(mph) x 3

Q11 is 9km per hour

210km = 30 mins(1/2hour)

1 min = 210/30

Q12 is 2hrs 30mins

2miles = 1hour

5miles = 5/2

mezya [45]4 years ago

6 0

Answer:

can you plz tell which numbers you have problem with

Step-by-step explanation:

You might be interested in

What is the difference between the sample average y and the population mean?

stepan [7]

When a finite number of samples are drawn from a larger population, the sample mean of that sample, while usually close to the population mean, is not the same thing. A population mean, on the other hand, is a description of pretty much ALL of whatever is being examined.

Example of population: Everyone in the USA
Example of a sample: One person, chosen at random, from each of the 50 states

3 0

3 years ago

In AOPQ, mZO = (6x – 14)°, mZP = (2x + 16)°, and mZQ = (2x + 8)°. Find mZQ.

loris [4]

$\measuredangle Q=42$

Explanation

Step 1

the sum of the internal angles in a triangle equals 18o, so

$\begin{gathered} (2x+16)+(6x-14)+(2x+8)=180 \\ 2x+16+6x-14+2x+8=180 \\ \text{add similar terms} \\ 10x+10=180 \\ \text{subtract 10 in both sides} \\ 10x+10-10=180-10 \\ 10x=170 \\ \text{divide both sides by 10} \\ \frac{10x}{10}=\frac{170}{10} \\ x=17 \end{gathered}$

Step 2

now, replace the value of x in angle Q to find it

$\begin{gathered} \measuredangle Q=(2x+8) \\ \measuredangle Q=(2\cdot17+8) \\ \measuredangle Q=(34+8) \\ \measuredangle Q=42 \end{gathered}$

I hope this helps you

8 0

1 year ago

[(-6,2),(2,3),(1,1),(-7,2),(4,2)]

denis-greek [22]

$\bf \begin{array}{llll}
&[(-6,2),(2,3),(1,1),(-7,2),(4,2)]\\\\
inverse& [(2,-6),(3,2),(1,1),(2,-7),(2,4)]
\end{array}
\\\\\\
\textit{is the original a one-to-one?}\qquad \stackrel{rep eated~y-values}{(-6,\stackrel{\downarrow }{2}),(2,3),(1,1),(-7,\stackrel{\downarrow }{2}),(4,\stackrel{\downarrow }{2})}$

notice, the inverse set is just, the same set with the x,y turned to y,x, backwards.

is it a one-to-one? well, for a set to be a one-to-one, it must not have any x-repeats, that is, the value of the first in the pairs must not repeat, and it also must not have any y-repeats, namely the value of the second in the pairs must not repeat.

6 0

3 years ago

(6/11) to the power 2 answer pls

Lana71 [14]

Step-by-step explanation:

in fraction it comes 36/121

and in decimal.it comes 0.3

5 0

3 years ago

Read 2 more answers

I don't know which one is the correct answer? PLEASE HELP!!

alukav5142 [94]