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3 years ago

Please click on the photo and answer ASAP!!!! Worth 90points!!!! Please also try to include working out!!!!

Mathematics

2 answers:

Oksanka [162]3 years ago

8 0

Answers: ( '/' means divides by)

Q4 is 720miles

mph = 240

3hrs = 240 x 3

Q5 is 31.5mph

2 hrs = 65miles

1mile = 65/2

Q6 is 4 hours

20miles in 1hour

80 miles = 80/20

Q7 is 3cm

30secs = 0.5cm

60sec(1min) = 60 x 0.5

Q8 is 15km per hour

5hrs = 75km

1hr = 75/5

Q9 is 7hrs 30mins

20miles per hour meaning 1 hour

150miles = 150/20

Q10 is 165miles

distance between 4pm and 7pm is 3 hours

55(mph) x 3

Q11 is 9km per hour

210km = 30 mins(1/2hour)

1 min = 210/30

Q12 is 2hrs 30mins

2miles = 1hour

5miles = 5/2

mezya [45]3 years ago

6 0

Answer:

can you plz tell which numbers you have problem with

Step-by-step explanation:

You might be interested in

Solve equation for the given variable

Alenkinab [10]

Answer:

p=30

Step-by-step explanation:

First, you need to subtract 10 from both sides to get 1/2p=25. You do this just because simplifying is much easier.

Then, you need to isolate p, so you divide 1/2 by both sides, which is the same thing as multiplying by 2. 1/2*2p=15*2.

Simplifying, you get p=30.

8 0

2 years ago

Read 2 more answers

The sum of five times a number and -6 is -2

koban [17]

So,

"The sum of five times a number and -6"
5n + -6 or 5n - 6

"is -2"
= -2

5n - 6 = -2

Add 6 to both sides.
5n = 4

Divide both sides by 5.
$n = \frac{4}{5} \ or\ 0.8\ or\ 80\ percent$

7 0

2 years ago

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

Please help me i’m desperateeee!!!

lara31 [8.8K]

Answer:

option no.D

6y+15x

Step-by-step explanation:

hope it helps

7 0

2 years ago

Solve for J MUST SHOW WORK<br> j/-2 + 7 = -12<br><br> thx!!

Ronch [10]

Answer:

j=38

Step-by-step explanation:

j/-2 +7=-12, subtract 7 from both sides of the equation and you get j/-2 = -19, then you multiply j/-2 by -2/1 and multiply -19 by -2/1 to get j= 38

5 0

2 years ago